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Mariana [72]
3 years ago
11

Please tell me the order the answers go. Best and most correct answer gets Brainliest.

Physics
1 answer:
iogann1982 [59]3 years ago
8 0

See the attached picture:

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A weightlifter works out at the gym each day. Part of her routine is to lie on her back and lift a 43 kg barbell straight up fro
Tasya [4]

Answer:

A. 231.77 J

B. 5330.71 J

C. 46 donuts

Explanation:

A. To lift the barbell once, she will have to extend it the full length of her arm. The work done will then be:

W = F * d

Where the force is the weight of the barbell.

F = m * g

Hence, the work done in lifting the barbell is:

W = m * g * d

W = 43 * 9.8 * 0.55

W = 231.77 J

B. If she does 23 repetitions, the total energy she expend will be equal to the Potential energy when the barbell is lifted multiplied by 23:

E = 23 * m * g * d

E = 23 * 231.77

E = 5330.71 J

C. 1 Joule = 4.184 calories

5330.71 Joules = 5330.71 * 4.184 = 22303.69

If 1 donut contains 490 calories, the number of donuts she will need will be:

N = 22303.69/490 = 45.5 donuts or 46 donuts

5 0
3 years ago
How did people manage to survive and thrive tens of thousands of years ago?
Debora [2.8K]

Answer: During medieval times, men, especially outlaws, would keep warm in the winter by wearing a linen shirt with underclothes, mittens made of wool or leather and woolen coats with a hood over a tight cap called a coif.

Explanation:

HOPE THAT HELPED A LITTLE

8 0
3 years ago
Read 2 more answers
Consider an electron with charge −e and mass m orbiting in a circle around a hydrogen nucleus (a single proton) with charge +e.
alexandr1967 [171]

Answer:

v=\sqrt{k\frac{e^2}{m_e r}}, 2.18\cdot 10^6 m/s

Explanation:

The magnitude of the electromagnetic force between the electron and the proton in the nucleus is equal to the centripetal force:

k\frac{(e)(e)}{r^2}=m_e \frac{v^2}{r}

where

k is the Coulomb constant

e is the magnitude of the charge of the electron

e is the magnitude of the charge of the proton in the nucleus

r is the distance between the electron and the nucleus

v is the speed of the electron

m_e is the mass of the electron

Solving for v, we find

v=\sqrt{k\frac{e^2}{m_e r}}

Inside an atom of hydrogen, the distance between the electron and the nucleus is approximately

r=5.3\cdot 10^{-11}m

while the electron mass is

m_e = 9.11\cdot 10^{-31}kg

and the charge is

e=1.6\cdot 10^{-19} C

Substituting into the formula, we find

v=\sqrt{(9\cdot 10^9 m/s) \frac{(1.6\cdot 10^{-19} C)^2}{(9.11\cdot 10^{-31} kg)(5.3\cdot 10^{-11} m)}}=2.18\cdot 10^6 m/s

7 0
3 years ago
Which statement about gravity is true?
SVETLANKA909090 [29]

Out of the given options, ‘it is described as a fundamental force and therefore does not depend on other forces’ is the true statement about gravity.

Answer: Option B

<u>Explanation: </u>

As we all know that there are four fundamental forces existing in the universe- Electromagnetic force, strong forces, weak forces and the gravitational force.

These are the forces that don’t depend on any other physical force to draw a considerable impact on the physical objects. The gravitational force can be defined as,

                     F=G \times \frac{m_{1} m_{2}}{r^{2}}

Where,

G = Gravitational Constant

m_{1} , m_{2} = Masses of two substances under consideration

R = distance between the two substances.

Looking upon the formula of gravitational force we can easily estimate that the gravitational force relies on the mass of substances and the relative distance between them. There is no factor than the air friction that hinders the gravitational force and that too in a negligible amount.

5 0
3 years ago
A "spherical capacitor" is constructed of two thin, concentric spherical shells of conducting material. Let a be the radius of t
Shalnov [3]

Answer:

C=\frac{ab}{k(b-a)}

Explanation:

We can assume this problem as two concentric spherical metals with opposite charges.

We have also to take into account the formulas for the electric field and the capacitance. Hence we have

C=\frac{Q}{V}\\\\E=k\frac{Q}{r^2}\\

Where k is the Coulomb's constant. Furthermore, by taking into account the expression for the potential and by integrating

dV=Edr\\\\V=\int_{R_1}^{R_2}Edr=-\int_{R_1}^{R_2}\frac{kQ}{r^2}dr\\\\V=kQ[\frac{1}{R_2}-\frac{1}{R_1}]

Hence, the capacitance is

C=\frac{1}{k[\frac{1}{R_2}-\frac{1}{R_1}]}

but R1=a and R2=b

C=\frac{ab}{k(b-a)}

HOPE THIS HELPS!!

3 0
3 years ago
Read 2 more answers
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