1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
zmey [24]
3 years ago
13

A/an bonds allows metals to conduct electricity

Chemistry
1 answer:
dalvyx [7]3 years ago
5 0
If I understand you correctly, you should fill the gap and decide which kind og bonds <span> allows metals to conduct electricity. If so, without any doubt I can say that the metalic bonds </span><span> allows metals to conduct electricity. I'm pretty sure it will help you! Regards.</span>
You might be interested in
What is the distinction between magma and lava​
BabaBlast [244]

Answer:

Scientists use the term magma for molten rock that is underground and lava for molten rock that breaks through the Earth's surface.

7 0
2 years ago
Read 2 more answers
What mass of salt is needed to prepare 600 mL of a 4g/L solution?
OLga [1]
THE ALTERNATIVE IS 4.8g alternative c
5 0
2 years ago
Explain how storm surges can affect human life in Florida.
Blizzard [7]
As a result of high winds and water from a storm surge, homes, businesses, and crops may be destroyed or damaged, public infrastructure may also be compromised, and people may suffer injuries or loss of life.
5 0
2 years ago
WILL GIVE BRANLIEST!! EASY BUT I WAS TO LAZY TO LEARN!! WILL FOREVER BE GREATFUL!!! WILL GIVE BRANLIEST!! EASY BUT I WAS TO LAZY
maxonik [38]

Answer:

3. Which side of the chain should you count from when naming organic compounds?

C) Side that will give you the longest Carbon chain

4. What is the pH of a solution with a pOH of 10?

C) 4

pH + pOH = 14

pH + 10 = 14

pH = 14 - 10

pH = 4

<u>-TheUnknownScientist</u>

3 0
3 years ago
Consider the following equilibrium: 2SO^2(g) + O2(9) = 2 SO3^(g)
saul85 [17]

Answer:

At equilibrium, the forward and backward reaction rates are equal.

The forward reaction rate would decrease if \rm O_2 is removed from the mixture. The reason is that collisions between \rm SO_2 molecules and \rm O_2\! molecules would become less frequent.

The reaction would not be at equilibrium for a while after \rm O_2 was taken out of the mixture.

Explanation:

<h3>Equilibrium</h3>

Neither the forward reaction nor the backward reaction would stop when this reversible reaction is at an equilibrium. Rather, the rate of these two reactions would become equal.

Whenever the forward reaction adds one mole of \rm SO_3\, (g) to the system, the backward reaction would have broken down the same amount of \rm SO_3\, (g)\!. So is the case for \rm SO_2\, (g) and \rm O_2\, (g).

Therefore, the concentration of each species would stay the same. There would be no macroscopic change to the mixture when it is at an an equilibrium.

<h3>Collision Theory</h3>

In the collision theory, an elementary reaction between two reactants particles takes place whenever two reactant particles collide with the correct orientation and a sufficient amount of energy.

Assume that \rm SO_2\, (g) and \rm O_2\, (g) molecules are the two particles that collide in the forward reaction. Because the collision has to be sufficiently energetic to yield \rm SO_3\, (g), only a fraction of the reactions will be fruitful.

Assume that \rm O_2\, (g) molecules were taken out while keeping the temperature of the mixture stays unchanged. The likelihood that a collision would be fruitful should stay mostly the same.

Because fewer \!\rm O_2\, (g) molecules would be present in the mixture, there would be fewer collisions (fruitful or not) between \rm SO_2\, (g) and \rm O_2\, (g)\! molecules in unit time. Even if the percentage of fruitful collisions stays the same, there would fewer fruitful collisions in unit time. It would thus appear that the forward reaction has become slower.

<h3>Equilibrium after Change</h3>

The backward reaction rate is likely going to stay the same right after \rm O_2\, (g) was taken out of the mixture without changing the temperature or pressure.

The forward and backward reaction rates used to be the same. However, right after the change, the forward reaction would become slower while the backward reaction would proceed at the same rate. Thus, the forward reaction would become slower than the backward reaction in response to the change.

Therefore, this reaction would not be at equilibrium immediately after the change.

As more and more \rm SO_3\, (g) gets converted to \rm SO_2\, (g) and \rm O_2\, (g), the backward reaction would slow down while the forward reaction would pick up speed. The mixture would once again achieve equilibrium when the two reaction rates become equal again.

5 0
2 years ago
Other questions:
  • The particle picture is best described as....
    14·2 answers
  • The weak acid HA is 2% ionized (dissociated) in a 0.20 M solution.
    14·1 answer
  • 26)Predict the products of the following chemical reaction
    5·1 answer
  • 1. To become stable, the following element:
    10·1 answer
  • How many moles of potassium are in 78.20 g?
    12·2 answers
  • The proton,neutron and electrons in the atom of the element represented by the symbol 231Y89 are:
    14·1 answer
  • Which of these solutions has the highest freezing point?
    6·2 answers
  • When an ice cube melts what happens to the matter that once made up the cube
    12·1 answer
  • What is the Percent yield made if 3.9 grams of a substance were made experimentally while you calculated 3.6 grams of substance
    11·1 answer
  • What is the word equation of photodecomposition?​
    13·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!