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antiseptic1488 [7]
3 years ago
9

What is the greatest common factor of 8n cubed and 20 n

Mathematics
2 answers:
Phantasy [73]3 years ago
5 0
The greatest common factor of 8n^3 and 20n is 4n
Alecsey [184]3 years ago
3 0
4 Is The Greatest Common Factor Between Both
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If lena has 5 kids and she has 9 more but loses 3 kids then she found 19 kids so she just kept them. how many kids now does she
Dahasolnce [82]
She has 30 children........
3 0
3 years ago
Read 2 more answers
CALCULUS: For an object whose velocity in ft/sec is given by v(t) = sin(t), what is its distance, in feet, travelled on the inte
rodikova [14]

The linked answer is wrong because that integral gives you the net displacement of the object, not the total distance.

To get the distance, you have to integrate the speed (as opposed to velocity), which involves integrating the absolute value of the velocity function.

\mathrm{distance} = \displaystyle\int_1^5 |\sin(t)| \,\mathrm dt

By definition of absolute value,

|\sin(t)|=\begin{cases}\sin(t)&\text{for }\sin(t)\ge0\\-\sin(t)&\text{for }\sin(t)

Over this particular integration interval,

• sin(<em>t</em> ) ≥ 0 for 1 ≤ <em>t</em> < <em>π</em>, and

• sin(<em>t</em> ) < 0 for <em>π</em> < <em>t</em> ≤ 5

so you end up splitting the integral at <em>t</em> = <em>π</em> as

\mathrm{distance} = \displaystyle\int_1^\pi \sin(t)\,\mathrm dt + \int_\pi^5 (-\sin(t))\,\mathrm dt

Now compute the distance:

\mathrm{distance} = -\cos(t)\bigg|_1^\pi + \cos(t)\bigg|_\pi^5

\mathrm{distance} = -(\cos(\pi) - \cos(1)) + (\cos(5) - \cos(\pi))

\mathrm{distance} = -2\cos(\pi) + \cos(1) + \cos(5) \approx 2.82

making B the correct answer.

7 0
2 years ago
Multiply the following polynomials, then place the answer in the proper location on the grid. Write the answer in descending pow
attashe74 [19]
32x^2+64x+12x+21 => 32x^2+76x+21 you multiply the two equation together and you will get this
4 0
2 years ago
Sheila I said going to divide a 36-inch piece of ribbon into 5 equal pieces she says each piece will be 7 inches long
blsea [12.9K]
Well it would actually be 7.2 inches per each piece
7 0
3 years ago
A car's velocity is modeled by
Igoryamba

In accordance with the function <em>velocity</em>, the car will have a complete stop after 6 seconds.

<h3>When does the car stop?</h3>

Herein we have a function of the velocity of a car (v), in feet per second, in terms of time (t), in seconds. The car stops for t > 0 and v = 0, then we have the following expression:

0.5 · t² - 10.5 · t + 45 = 0

t² - 21 · t + 90 = 0

By the <em>quadratic</em> formula we get the following two roots: t₁ = 15, t₂ = 6. The <em>stopping</em> time is the <em>least</em> root of the <em>quadratic</em> equation, that is, the car will have a complete stop after 6 seconds.

To learn more on quadratic equations: brainly.com/question/2263981

#SPJ1

8 0
1 year ago
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