Question 6 (3 points)
1 answer:
Answer:
Explanation:
Given parameters:
Molarity of KOH = 0.26M
Volume of H₂SO₄ = 19.76mL
Molarity of H₂SO₄ = 0.20M
Unknown:
Volume of KOH = ?
Solution:
This is a neutralization reaction in which an acid reacts with a base to produce salt and water:
H₂SO₄ + 2KOH → K₂SO₄ + 2H₂O
We solve from the known to the unknown in the reaction.
The known is the acid and from there we can find the number of moles of the acid to be completely neutralized:
Number of moles of acid = molarity x volume
Number of moles of acid = 19.76 x 0.20 = 3.95mol
From the balanced reaction equation:
1 mole of acid reacts with 2 moles of the bases KOH
3.95mole of acid would react with 3.95moles x 2 of the base
Number of moles of reacting base = 7.90moles
To find the volume of base;
Volume of base =
Volume = = 30.40mL
Learn more:
Neutralization brainly.com/question/6447527
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Answer: The final molarity of the diluted oxalic acid solution is 0.0032 M
Explanation:
Molarity: It is defined as the number of moles of solute present per liter of the solution.
Formula used :
where,
n= moles of solute
Moles=
= volume of solution in ml
To calculate the final molarity of the diluted oxalic acid solution
where,
are the molarity and volume of concentrated oxalic acid solution.
are the molarity and volume of diluted oxalic acid solution.
We are given:
Putting values in above equation, we get:
Thus the final molarity of the diluted oxalic acid solution is 0.0032 M