the mean of school lunches is 5
Answer:
Dimensions are 20 X 44 feet
Step-by-step explanation:
First we need to build two equations:
For area X times Y = 880
For Perimeter 2x + 2y = 128
Now we need to solve one so we can substitute it into the other:
2x + 2y = 128 becomes
2x = 128 - 2y and then
x = 64 - y We will substitute this into the are equation
(64 - y)y = 880
64y -
= 880
-
factor out the negative
-(
Factor:
-(y - 20)(y - 44) = 0
y-20 = 0 and y - 44 = 0
y = 20 and y = 44
Plugging these in two both of our formulas works
20 X 44 = 880 for area
2(20) + 2 (44) = 128 for perimeter
Given:
The cost of adults ticket = $18
The cost of children's ticket = $8.25
Total tickets = 2300
Total revenue = $30,168.
To find:
The number of children and number of adults attended the zoo that day.
Solution:
Let x be the number of children and y be the number of adults.
Equation for tickets:
...(i)
Equation for revenue:
...(ii)
Plot the graphs of the given equations on a coordinate plane as shown below.
From the graph it is clear that the graph of both equations intersect each other at (1148,1152).
It means the number of adults is 1148 and the number of children is 1152.
It can be solved algebraically as shown below:
Substitute the value of y in (ii) from (i).




Divide both sides by 9.75.


Putting
in (i), we get



Therefore, the number of adults is 1148 and the number of children is 1152.
Answer:
no, it'll become -10. 9 will be greater
Step-by-step explanation: