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Yakvenalex [24]
3 years ago
8

Describe the molecular structure of water and explain why the water molecule is polar

Chemistry
1 answer:
pentagon [3]3 years ago
8 0

Explanation:

Hybridization of O in H_2O = sp^3

So, water molecule has four hybrid orbitals.

Two hybrid orbitals form 2 sigma bond with two H atoms.

Remaining two hybrid orbitals are occupied by two lone pairs.

Because of lone pair-lone pair repulsion, shape of H_2O becomes bent.

Water molecule is polar because of difference in eletronegativities of O and H.

O is more electronegative as comapared to hydrogen. So bonding electrons get attracted towards O atom which results in the development of partial negative charge on O atom and partial positive charge on H atoms.

Because of development of partial negative and partial positive charge, water molecule becomes polar.

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<h3><u>Ⲁⲛ⳽ⲱⲉⲅ</u><u>:</u></h3>

\quad\hookrightarrow\quad \sf {0.262M }

<h3><u>Ⲋⲟⳑⳙⲧⳕⲟⲛ :</u></h3>

Molarity is used to measure the concentration of a solution , so it is also as molar concentration. It is denoted as M or Mol/L

<u>We </u><u>are </u><u>given </u><u>that </u><u>:</u>

  • Weight of \sf MgCl_{2} = 5.34g
  • Volume of solution = 214 ml , or 0.214 L

The molar mass of magnesium chloride ( \sf MgCl_{2} ) is 95.21 g / mol

We can calculate the molarity of the solution by dividing the number of moles of solute by volume of solvent in liter ,i.e:

\quad\longrightarrow\quad \sf  {M = \dfrac{n}{V} } ‎ㅤ‎ㅤ‎ㅤ⸻( 1 )

<em>Where,</em><em> </em>

  • M = molarity
  • n = number of moles
  • V = Volume

We can calculate the number of moles by dividing the actual mass by its molar mass ,i.e:

\quad\longrightarrow\quad \sf { n = \dfrac{w}{m}}‎ㅤ‎ㅤ‎ㅤ‎⸻ ( 2 )

<em>W</em><em>here,</em>

  • n = number of moles
  • m = molar mass
  • w = actual mass

<u>Therefore</u><u>,</u>

\implies\quad \tt {n =\dfrac{w}{m} }

\implies\quad \tt { n =\dfrac{5.35\: g}{95.21\: g /mol}}

\implies\quad{\pmb{ \tt {n = 0.056 mol}} }

<u>P</u><u>utting </u><u>the </u><u>values </u><u>in </u><u>equation </u><u>(</u><u> </u><u>1</u><u> </u><u>)</u><u>:</u>

\implies\quad \tt {M=\dfrac{n}{V} }

\implies\quad \tt { M =\dfrac{0.056\:mol}{0.214\:L}}

\implies\quad\underline{\pmb{ \tt { M = 0.262 \:M }}}

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