Answer:
The mass of the aluminum chunk is 258 g
Explanation:
Given;
mass of steel container = 120-g
mass of water = 150 g
initial temperature of water, = 25°C
mass of copper cube,
= 200 g
initial temperature of the copper cube,
= 85°C
initial temperature of the aluminum chunk
= 5.0°C
Neglecting heat loss, heat exchanged by the two metallic objects is the same since initial temperature is equal to final temperature of water.
![M_{Al}C_{Al} \delta T_{Al} = M_{cu}C_{cu} \delta T_{cu}](https://tex.z-dn.net/?f=M_%7BAl%7DC_%7BAl%7D%20%5Cdelta%20T_%7BAl%7D%20%3D%20M_%7Bcu%7DC_%7Bcu%7D%20%5Cdelta%20T_%7Bcu%7D)
where;
is specific heat capacity of aluminum
is change in temperature of aluminum
is the specific heat capacity of copper
is the change in temperature of copper
![M_{Al}C_{Al} \delta T_{Al} = M_{cu}C_{cu} \delta T_{cu} \\\\M_{Al} = \frac{M_{cu}C_{cu} \delta T_{cu}}{C_{Al} \delta T_{Al}} \\\\M_{Al} = \frac{0.2*387*60}{900*20} = 0.258 \ kg](https://tex.z-dn.net/?f=M_%7BAl%7DC_%7BAl%7D%20%5Cdelta%20T_%7BAl%7D%20%3D%20M_%7Bcu%7DC_%7Bcu%7D%20%5Cdelta%20T_%7Bcu%7D%20%5C%5C%5C%5CM_%7BAl%7D%20%3D%20%5Cfrac%7BM_%7Bcu%7DC_%7Bcu%7D%20%5Cdelta%20T_%7Bcu%7D%7D%7BC_%7BAl%7D%20%5Cdelta%20T_%7BAl%7D%7D%20%5C%5C%5C%5CM_%7BAl%7D%20%3D%20%5Cfrac%7B0.2%2A387%2A60%7D%7B900%2A20%7D%20%3D%200.258%20%5C%20kg)
Therefore, the mass of the aluminum chunk is 258 g