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Assoli18 [71]
3 years ago
12

A runner circles a 300 meter track exactly 4 times. What is the runner’s total displacement?

Physics
1 answer:
kakasveta [241]3 years ago
6 0

Answer:

1,200

Explanation:

300x4=1200

I hope this helps you

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Which statement explains how it is possible to carry books to school without changing the kinetic or potential energy of the boo
Mamont248 [21]

Answer:

a. by moving the book without acceleration and keeping the height of the book constant

Explanation:

FOR CONSTANT KINETIC ENERGY:

The kinetic energy of a body depends upon its speed according to its formula:

ΔK.E = (1/2)mΔv²

So, for Δv = 0 m/s

ΔK.E = 0 J

So, for keeping kinetic energy constant, the books must be moved at constant speed without acceleration.

FOR CONSTANT POTENTIAL ENERGY:

The potential energy of a body depends upon its height according to its formula:

ΔP.E = mgΔh

So, for Δh = 0 m/s

ΔP.E = 0 J

So, for keeping potential energy constant, the books must be moved at constant height.

So, the correct option is:

<u>a. by moving the book without acceleration and keeping the height of the book constant</u>

8 0
3 years ago
Which of the following does each different kind of atom represent?
r-ruslan [8.4K]

Answer:

B

Explanation:

because atoms make up an element.

5 0
4 years ago
Read 2 more answers
Calculate the minimum thickness (in nm) of an oil slick on water that appears blue when illuminated by white light perpendicular
mr_godi [17]

Answer:

The minimum thickness = 83.92 nm

Explanation:

The relation between the wavelength in a particular medium and refractive index \lambda_n = \frac{ \lambda }{n}

where ;

\lambda = wavelength of the light in vacuum

n = refractive index of medium with respect to vacuum

For one phase change :

2t = \frac{\lambda_n}{2}\\\\where \ \lambda_n = \frac{\lambda}{n}\\\\Then \ \\\\2t = \frac{\lambda}{2n}\\\\t = \frac{\lambda_n}{4n}

Replacing 1.43 for n and 480 nm for λ; we have:

t = \frac{480}{4(1.43)}

t = 83.92 nm

Thus; the minimum thickness = 83.92 nm

4 0
3 years ago
Phobos's Orbit. Phobos orbits Mars at a distance of 9,380 km from the center of the planet and has a period of 0.3189 days. Assu
Elenna [48]

Answer:

Explanation:

The relation between time period of moon in the orbit around a planet can be given by the following relation .

T² = 4 π² R³ / GM

G is gravitational constant , M is mass of the planet , R is radius of the orbit and T is time period of the moon .

Substituting the values in the equation

(.3189 x 24 x 60 x 60 s)²  = 4 x 3.14² x ( 9380 x 10³)³ / (6.67 x 10⁻¹¹ x M)

759.167 x 10⁶ = 8.25 x 10²⁰ x 39.43 / (6.67 x 10⁻¹¹ x M )

M = .06424  x 10²⁵

= 6.4 x 10²³ kg .

4 0
3 years ago
light travels approximately 982,080,000 ft/s, and one year has approximately 32,000,000 seconds. A light year is the distance li
lapo4ka [179]

Answer:

The distance traveled in 1 year is: 3.143*10^{16}ft

Explanation:

Given

s = 982,080,000 ft/s --- speed

t = 32,000,000 s --- time

Required

The distance traveled

This is calculated as:

Speed = \frac{Distance}{Time}

So, we have:

Distance = Speed * Time

This gives:

Distance = 982,080,000 ft/s * 32,000,000 s

Distance = 982,080,000  * 32,000,000ft

Distance = 3.143*10^{16}ft -- approximated

5 0
3 years ago
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