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lakkis [162]
1 year ago
13

A sound with a lot of energy is ____________________ than a sound with less energy.

Physics
1 answer:
Zielflug [23.3K]1 year ago
3 0

Louder than a sound with less energy

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A bowl contains 4 red balls and 2 green balls. Two balls are selected simultanesouly and at random. What is the conditional prob
AlladinOne [14]

Answer:0.6

Explanation:

Given

Bowl contains 4 red and 2 Green balls

Probability of selecting two red balls given atleast one of the ball is red + Probability of selecting two red balls given that no ball is red =1

Probability of selecting two red balls given that no ball is red =\frac{Probability \ of\ selecting\ two\ red\ balls\ out\ of\ 4\ balls}{probability\ of\ selecting\ 2\ balls\ out\ of\ 6 balls}

P=\frac{^{4}C_2}{^{6}C_2}

P=\frac{2}{5}

Required Probability=1-\frac{2}{5}=\frac{3}{5}

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3 years ago
What is the frequency of a wave whose wavelength is 0.7m and whose velocity is 120m/s?
ANEK [815]

Answer:

f=171.43Hz

Explanation:

Wave frequency is the number of waves that pass a fixed point in a given amount of time.

The frequency formula is: f=v÷λ, where <em>v</em> is the velocity and <em>λ</em> is the wavelength.

Then replacing with the data of the problem,

f=\frac{120\frac{m}{s} }{0.7m}

f=171.43\frac{1}{s}

f=171.43 Hz (because \frac{1}{s} = Hz, 1 hertz equals 1 wave passing a fixed point in 1 second).

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<span>Px = 0 Py = 2mV second, Px = mVcosφ Py = –mVsinφ add the components Rx = mVcosφ Ry = 2mV – mVsinφ Magnitude of R = âš(Rx² + Ry²) = âš((mVcosφ)² + (2mV – mVsinφ)²) and speed is R/3m = (1/3m)âš((mVcosφ)² + (2mV – mVsinφ)²) simplifying Vf = (1/3m)âš((mVcosφ)² + (2mV – mVsinφ)²) Vf = (1/3)âš((Vcosφ)² + (2V – Vsinφ)²) Vf = (V/3)âš((cosφ)² + (2 – sinφ)²) Vf = (V/3)âš((cos²φ) + (4 – 2sinφ + sin²φ)) Vf = (V/3)âš(cos²φ) + (4 – 2sinφ + sin²φ)) using the identity sin²(Ď)+cos²(Ď) = 1 Vf = (V/3)âš1 + 4 – 2sinφ) Vf = (V/3)âš(5 – 2sinφ)</span>
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if somthing is warm or if somthing moves it usally has energy

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