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Colt1911 [192]
3 years ago
7

The gravitational force between the charged constituents of the atom is negligible compared with the electric force between them

. The electric force is so strong, however, that any net charge on an object quickly attracts nearby opposite charges, neutralizing the object. As a result, gravity plays a greater role in the mechanics of moving objects in everyday life. QUESTION If the distance between two charges is doubled, by what factor is the magnitude of the electric force changed?
Physics
1 answer:
katrin2010 [14]3 years ago
6 0

Answer: The initial force is reduced a factor 1/4 when the separation between charge is doubled

Explanation: As it well known the electric force between two charges is given by:

Finitial=k*q1*q2/d^2 where d is the distance between charges and k is a constant

if the distance is doubled this means 2*dinitial thus the new force is equal to F initial* 1/4

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A very narrow beam of white light is incident at 40.80° onto the top surface of a rectangular block of flint glass 11.6 cm thick
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Dispersion angle = 0.3875 degrees. 
Width at bottom of block = 0.09297 cm 
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 n1*sin(θ1) = n2*sin(θ2)
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 n1, n2 = indexes of refraction for the different mediums
 Î¸1, θ2 = angle of incident rays as measured from the normal to the surface. 
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 n1*sin(θ1) = n2*sin(θ2)
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 asin(n1*sin(θ1)/n2) = θ2 
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 asin(n1*sin(θ1)/n2) = θ2
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 asin(1.00029*0.653420604/1.667) = θ2
 asin(0.39208764) = θ2
 23.08446098 = θ2 
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 23.47193844 - 23.08446098 = 0.38747746 degrees. 
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 11.6*0.434230136 = X
 5.037069579 = X 
 And violet:
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 11.6*tan(23.08446098) = X
 11.6*0.426215635 = X
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 cos(θ) = X/0.092968218
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