Answer:
The the intensity at an 11° angle to the axis in terms of the intensity of the central maximum is

Explanation:
From the question we are told that
The width of the slit is 
The wavelength is 
The angle is 
The intensity of at
to the axis in terms of the intensity of the central maximum. is mathematically represented as
![I_c = \frac{I}{I_o} = [ \frac{sin \beta }{\beta }] ^2](https://tex.z-dn.net/?f=I_c%20%3D%20%5Cfrac%7BI%7D%7BI_o%7D%20%20%3D%20%5B%20%5Cfrac%7Bsin%20%5Cbeta%20%20%7D%7B%5Cbeta%20%7D%5D%20%5E2)
Where
is mathematically represented as

substituting values


So
![I_c = \frac{I}{I_o} = [ \frac{sin (708.1) }{(708.1)}] ^2](https://tex.z-dn.net/?f=I_c%20%3D%20%5Cfrac%7BI%7D%7BI_o%7D%20%20%3D%20%5B%20%5Cfrac%7Bsin%20%28708.1%29%20%20%7D%7B%28708.1%29%7D%5D%20%5E2)

Inertia: <span>The </span>law<span> of </span>inertia says <span>that an object at rest stays at rest and an object in motion stays in motion unless a force does something.</span>
Very good question, The answer you might be looking for is 7.467m/s^2.
Have a blessed day God bless.