The third question requires you to solve for the weight of sodium (Na) and weight of Chloride (Cl) from the calculated moles of each element Na, and Cl.
So, you need to multiply the calculated moles of Na with its molar mass (23 g/ mol) to get the answer for Na. And multiply the calculated moles of Cl with its molar mass (35.45 g/mol) to get the answer for Cl.
Answer:
The force of the gases pushes downward at the same time that the gases push the rocket upwards. 1.
Explanation:
Answer: The reactivity of acetic acid with various chemicals (A)
Explanation: engenuity 2021
Answer:
106.25 mL
Explanation:
For this, we can use
C1×V1=C2×V2
C1 = 0.45
V1 = 85
C2= 0.20
V2= ?
0.45 × 85 = 0.20 × V2
V2= (0.45 × 85)/0.20
V2=191.25mL
To find the amount of water added, subtract V1 from V2
191.25 - 85 =106.25mL
