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Rzqust [24]
2 years ago
5

What are the The properties of solids, liquids and gases are explained by

Chemistry
1 answer:
blsea [12.9K]2 years ago
5 0

Answer:

A Newton's Laws

Explanation:

Hopefully this helps

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Convert -32 F into K
Afina-wow [57]

Answer:

-32 Fahrenheit converts to 237.594 Kelvin

4 0
3 years ago
which of the following is a balanced chemical equation for the reaction of magnesium with nitrogen gas to form magnesium nitride
ioda
So the unbalanced equation would be Mg + N^2 --> Mg^3N^2

Which means the balanced equation would be 3Mg + N^2 --> Mg^3N^2

This is balance the equation out since you now has 3 magnesium and 2 nitrogen on the left side, and 3 magnesium on 2 nitrogen on the right. Double check my work though, it's been awhile.
8 0
3 years ago
Identify the only polyatomic ion below that is NOT an oxyanion. Your answer: A Cyanide B Nitrate C Hydroxide D Sulfate​
DochEvi [55]

Answer:

Cyanide

Explanation:

<em>Molecular Structure of Each Answer</em>

A:  CN-

B: NO3-

C: OH-

D: SO4 2-

As you can see, only A (Cyanide) is the only compound that does not contain oxygen, meaning it is NOT an oxyanion.

7 0
3 years ago
In what form does the sun's energy arrive on Earth?The physical characteristics of two large predatory animal species are shown
eimsori [14]

Answer:

radiation B species x because short canines are less likely to break.

6 0
2 years ago
The unheated Gas in the above system has a volume of 20.0 L at a temperature of 25.0 C and a pressure of 1.00 atm. The gas is he
kipiarov [429]

Answer:

1.25 atm.

Explanation:

Step 1:

Data obtained from the question. This includes the following:

Initial volume (V1) = 20L

Initial temperature (T1) = 25°C

Initial pressure = 1 atm

Final temperature (T2) = 100°C

Final volume (V2) = constant i.e remain the same

Final pressure (P2) =?

Step 2:

Conversion of celsius temperature to Kelvin temperature. This is illustrated below:

Temperature (Kelvin) = temperature (celsius) + 273

Initial temperature (T1) = 25°C = 25°C + 273 = 298K

Final temperature (T2) = 100°C = 100°C + 273 = 373K

Step 3:

Determination of the final pressure of the gas. This is illustrated below:

Since the volume is constant, the following equation, P1/T1 = P2/T2 will be used to obtain the final pressure of gas as follow:

P1/T1 = P2/T2

Initial temperature (T1) = 298k

Initial pressure = 1 atm

Final temperature (T2) = 373K

Final pressure (P2) =?

P1/T1 = P2/T2

1/298 = P2 /373

Cross multiply to express in linear form

298 x P2 = 1 x 373

Divide both side by 298

P2 = 373/298

P2 = 1.25 atm.

Therefore, the pressure of the heated gas is 1.25 atm.

3 0
3 years ago
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