Answer:
The right answer is:
Replacing the powdered lead oxide with its large crystals
Removing lead (IV) oxide from the reaction mixture
Using 1.0 gram of lead (IV) oxide
Explanation:
Based on the given information this reaction is the catalytic decomposition of H₂O₂ into water and oxygen using Lead (IV) oxide as a catalyst.
- The catalyst surface area is directly proportional to the reaction rate
- So, Replacing the powdered lead oxide with its large crystals would decrease the reaction rate due to the has larger surface area than its large crystals.
2. Also, Removing lead (IV) oxide from the reaction mixture the reaction rate decreased because as the catalyst is removed.
3. Using 50 cm³ of hydrogen peroxide doesn't affect the rate because the concentration of the reactant doesn't change.
4. Using 1.0 gram of lead (IV) oxide would decrease the reaction rate because the amount of catalyst decreased
So, The right answer is:
Replacing the powdered lead oxide with its large crystals
Removing lead (IV) oxide from the reaction mixture
Using 1.0 gram of lead (IV) oxide
Since the ethanol has a density of 0.800 g/mL, the mass of the ethanol is 180 grams.
<u>Given the following data:</u>
- Volume of ethanol = 225 mL
- Density of lead ball = 0.800 g/mL.
To find the mass of the ethanol;
Density can be defined as mass all over the volume of an object.
Mathematically, the density of a substance is given by the formula;
Making mass the subject of formula, we have;
Substituting the given parameters into the formula, we have;
<em>Mass of ethanol </em><em>=</em><em> 180 grams.</em>
Read more: brainly.com/question/18320053
Explanation:
Molar mass
The mass present in one mole of a specific species .
The molar mass of a compound , can easily be calculated as the sum of the all the individual atom multiplied by the number of total atoms .
(a) P₄
Molar mass of of the atoms are -
Phosphorous , P = 31 g/mol
Molecular mass of P₄ = ( 4 * 31 ) = 124 g/mol .
(b) H₂O
Molar mass of of the atoms are -
Hydrogen , H = 1 g/mol
oxygen , O = 16 g/mol.
Molecular mass of H₂O = ( 2 * 1 ) + ( 1 * 16 ) = 18 g/mol
(c) Ca(NO₃)₂
Molar mass of of the atoms are -
calcium , Ca = 40 g/mol
nitrogen, N = 14 g/mol
oxygen , O = 16 g/mol.
Molecular mass of Ca(NO₃)₂ = ( 1 * 40 ) + ( 2 * 14 ) + ( 6 * 16 ) = 164 g/mol.
(d)CH₃CO₂H (acetic acid)
Molar mass of of the atoms are -
Carbon , C = 12 g/mol.
oxygen , O = 16 g/mol.
Hydrogen , H = 1 g/mol
Molecular mass of CH₃CO₂H =( 2 * 12 ) + (2 * 16 ) + (4 * 1 ) = 60 g/mol.
(e) C₁₂H₂₂O₁₁ (sucrose, cane sugar).
Molar mass of of the atoms are -
Carbon , C = 12 g/mol.
oxygen , O = 16 g/mol.
Hydrogen , H = 1 g/mol
Molecular mass of C₁₂H₂₂O₁₁ = (12 * 12 ) + ( 22 * 1 ) + ( 11 * 16 ) = 342 g/mol.
Answer:
Erosion occurs through deflation, and sand that was picked up is deposited against an obstruction.
Explanation:
Erosion can be defined as a geological process which involves the wearing away of earth material and transportation of these material to another location by Natural agents such as wind and water. Erosion involves removal of top soil, rocks and other earth particles by action of wind, glacier and water.
Wind causes erosion by deflation. Deflation is the actual removal of grain of rocks . Generally, it s the lowering of land surface that happens as a result of removal of surface particles(sands grains) by wind. Deflation is usually prevalent in arid areas. This sand can later be picked up and deposited to form sand dunes . Sand dunes are mounds of sand formed by wind . This sands are sheltered by an obstacle. And sand dunes are prevalent in desert and or along the beach. The sand dune grows as sand accumulate.
