Answer:
The highest grade level is college.
Answer:
304.13 mph
Explanation:
Data provided in the question :
The Speed of the flying aircraft = 300 mph
Tailwind of the true airspeed = 50 mph
Now,
The ground speed will be calculated as:
ground speed = ![\sqrt{300^2+50^2}](https://tex.z-dn.net/?f=%5Csqrt%7B300%5E2%2B50%5E2%7D)
or
The ground speed = ![\sqrt{92500}](https://tex.z-dn.net/?f=%5Csqrt%7B92500%7D)
or
The ground speed = 304.13 mph
Hence, the ground speed is 304.13 mph
Rubber block is not shown. I have attached an image of it.
Answer:
A) ε_x = 0.0075
B) ε_y = 0.00375
C) γ_xy = 0.0122 rad
Explanation:
We are given;
δ = 0.03 in
L = 4 in
ν_r = 0.5
θ = 89.3° = 89.3π/180 rad
Let's calculate ε_x in the direction of axis x
Thus, ε_x = δ/L = 0.03/4 = 0.0075
Let's calculate ε_y in the direction of axis y;
ε_y = v•ε_x = 0.5 x 0.0075 = 0.00375
Now, shear strain is angle between π/2 rad surfaces at that point.
Thus,
γ_xy = π/2 - θ = π/2 - 89.3π/180
γ_xy = π(0.003889) = 0.0122 rad
Answer:
I would say that it is forming.
Explanation:
Give brainliest if u can. :S
Answer:
too big, too small, deadlines, not enough materials
Explanation: