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KIM [24]
3 years ago
10

A car is stopped at an entrance ramp to a freeway; its driver is preparing to merge. At a certain moment while stopped, this dri

ver observes a platoon of vehicles a distance x0 upstream and initiates the merge maneuver. The platoon approaches the entrance ramp at a constant speed v. The stopped car can accelerate from speed 0 to v at uniform acceleration rate a .
Find the latest time at which the stopped car can safely start the merge maneuver; i.e., derive an expression for the "latest safe start time" in terms of the variables x0, v and a. Assume this latest time enables the platoon to maintain its constant speed and "just touch" the merging car's trajectory. Ignore the physical dimensions of the car.
Engineering
1 answer:
Sophie [7]3 years ago
4 0

Answer:

T = \sqrt{\frac{2X_{0} }{a} }

Explanation:

Given,

Initial Velocity, u=0

As platoon is moving with constant velocity v,

Final Velocity, v=v

The vehicle starts from 0 to v at constant acceleration of a,

Relevent expressions:

v=u+at...........................(1)

v2=u2+2as.....................(2)  

V^{2} = 2aS, as S = X_{0},

V^{2} = 2aX_{0},

From(1)

v=at

Hence

(at)^2=2aX_{0}

T^{2}   =  \frac{2aX_0}{a^{2} }

T = \sqrt{\frac{2X_{0} }{a} }

This is the final expression for time.

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