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Kitty [74]
3 years ago
6

The climate of a location is affected by the presence of

Physics
2 answers:
Setler [38]3 years ago
6 0
<span><span>The climate of a location is affected by the presence of A Oceans.

</span>There are some climates factors that might affect the temperature of a location, these factors are latitude and attitude as well as distance from waterly places such as oceans (ocean currents).
Places along the coasts would be prevented from extremes hot or cold climates. </span>
alekssr [168]3 years ago
4 0
The answer is; oceans. I think this is the answer as the others do not make sense.

<em>Hope this helped! :)</em>
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A student connects a small solar panel to a 40 a resistor to make a simple circuit. The solar panel produces a voltage of 2 0.
Nastasia [14]
<h3>Solution for the above question : -</h3>

Ohm's law states that :

  • v = ir

the terms used are :

  • r = resistance
  • v = potential \:  \: difference
  • i  = current

let's solve for electric current :

  • 2 = i \times 40

  • i =  \dfrac{2}{40}

  • i = 0.05 \: A

  • i = 50 \: mA

\mathfrak{good\:  \: luck \:  \: for \:  \: your \:  \: assignment}

8 0
2 years ago
A fighter jet accelerates from 10 m/s to 75 m/s in 7.0 s. The acceleration of the jet is
liraira [26]
Acceleration = final velocity - inital / time
a = 75-10 / 7
a = 65 / 7
a = 9.29 m/s^2

4 0
2 years ago
Which of the following statements describes a battery?
LiRa [457]

Answer:

The negative electrode of a battery has an excess of positive charge

Explanation:

This is because in every battery, there is a negative electrode ( cathode ) and only positive charge is deposited on it.

For other statements:

Batteries donot store electric charge but they store chemical energy

Some batteries donot use metals for the flow of electrons, but some use hydrogen gas at a pressure of 1 atmosphere.

8 0
3 years ago
A steady beam of alpha particles (q = + 2e, mass m = 6.68 × 10-27 kg) traveling with constant kinetic energy 22 MeV carries a cu
cluponka [151]

Answer:

Explanation:

q = 2e = 3.2 x 10^-19 C

mass, m = 6.68 x 10^-27 kg

Kinetic energy, K = 22 MeV

Current, i = 0.27 micro Ampere = 0.27 x 10^-6 A

(a) time, t = 2.8 s

Let N be the alpha particles strike the surface.

N x 2e = q

N x 3.2 x 10^-19 = i t

N x 3.2 x 10^-19 = 0.27 x 10^-6 x 2.8

N = 2.36 x 10^12

(b) Length, L = 16 cm = 0.16 m

Let N be the alpha particles

K = 0.5 x mv²

22 x 1.6 x 10^-13 = 0.5 x 6.68 x 10^-27 x v²

v² = 1.054 x 10^15

v = 3.25 x 10^7 m/s

So, N x 2e = i x t

N x 2e = i x L / v

N x 3.2 x 10^-19 = 2.7 x 10^-7 x 0.16 / (3.25 x 10^7)

N = 4153.85

(c) Us ethe conservation of energy

Kinetic energy = Potential energy

K = q x V

22 x 1.6 x 10^-13 = 2 x 1.5 x 10^-19 x V

V = 1.17 x 10^7 V

5 0
3 years ago
The nuclear equation is incomplete.<br><br><br>What particle completes the equation?​
Romashka-Z-Leto [24]

Answer:

_{6}^{12} C

Explanation:

_{1}^{1}H+_{7}^{15}N --->    _{6}^{12} C+ _{2}^{4}He

1+7 = 6+2 =8 -protons

1+15 = 12+4 = 16 -  protons +neutrons

3 0
3 years ago
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