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matrenka [14]
3 years ago
11

How much of the Moon is always illuminated one time? Explain your answer.

Physics
1 answer:
Natalija [7]3 years ago
6 0

Answer:

50% of it .

Explanation:

50% of it is illuminated by the Sun.

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Which answer explains why plate B is moving underneath plate A
blsea [12.9K]

Answer:

A.

Explanation:

Earth is composed of different layers and one layer moves over another due to differences in the densities.

According to the physics of density, a substance having less density floats over a higher density substance. The oceanic crust has more density than the continental crust that is why continental crust float over oceanic crust.

So in the given example, plate B is moving below the plate A, it means plate B is more dense than plate A because plate B is composed of oceanic crust . <u>For example : continents float over the asthenosphere (a layer below the lithosphere).</u>

Hence, the correct answer is "A ".

4 0
3 years ago
If an object aquires additional energy, it is also aquiring additional: a) taxes b) vitamins c) mass d) pressure e) buoyancy
ludmilkaskok [199]

Answer:

Option c) mass

Explanation:

With the increase in energy in energy of an object there will be an increase in its mass.

Also from Einstein's mass-energy equivalence,

E = mc^{2}

where

m = mass of the object

c = speed of the object (usually speed of light or close to it)

which states that energy and mass are inter convertible.

From which it can be concluded that if an object acquires additional energy, it also acquires additional mass.

3 0
4 years ago
PLEASE HELLP ILL GIVE BrAINLY AND HEART
ipn [44]

Answer:

D

Explanation:

5 0
3 years ago
What is the formula for potassium iodide
musickatia [10]
Potassium iodide

Molar mass: 166.0028 g/mol

Formula: KI
3 0
3 years ago
Read 2 more answers
A 2.1 ✕ 103-kg car starts from rest at the top of a 5.9-m-long driveway that is inclined at 19° with the horizontal. If an avera
Lina20 [59]

Answer:

3.9 m/s

Explanation:

We are given that

Mass of car,m=2.1\times 10^3 kg

Initial velocity,u=0

Distance,s=5.9 m

\theta=19^{\circ}

Average friction force,f=4.0\times 10^3 N

We have to find the speed of the car at the bottom of the driveway.

Net force,F_{net}=mgsin\theta-f=2.1\times 10^3\times 9.8sin19-4.0\times 10^3

Where g=9.8 m/s^2

Acceleration,a=\frac{F_{net}}{m}=\frac{2.1\times 10^3\times 9.8sin19-4.0\times 10^3}{2.1\times 10^3}

v=\sqrt{2as}

v=\sqrt{2\times \frac{2.1\times 10^3\times 9.8sin19-4.0\times 10^3}{2.1\times 10^3}\times 5.9}

v=3.9 m/s

7 0
3 years ago
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