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3 years ago

How much of the Moon is always illuminated one time? Explain your answer.

Physics

1 answer:

Natalija [7]3 years ago

6 0

Answer:

50% of it .

Explanation:

50% of it is illuminated by the Sun.

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A chemist has two compounds that do not chemically react. He thinks that by finding the right catalyst, he can get them to react

8090 [49]

Answer:

The chemist is incorrect because a catalyst increases the rate of reaction only.

Explanation:

A catalyst is a substance in the presence of which the speed of the reaction increases. It plays no role in the chemical change taking place.

Thus, if the two compounds are not chemically reacting, a catalyst wont make it happen either.

A chemical reaction occurs when atoms tend to lose or gain electrons. A catalyst has no role to play in this process.

7 0

4 years ago

Read 2 more answers

Sally accelerates a 250 kg cart at 3 m/s/s. What must be the net force?

Vlad1618 [11]

750 N is what I got...

7 0

3 years ago

Pls I need it fast , its for my homework and I can’t find it

frez [133]

Answer:

first one is series second one is paralle

Explanation:

5 0

3 years ago

A cart of mass M = 2.40 kg can roll without friction on a level track. A light string draped over a light, frictionless pulley c

sergiy2304 [10]

Answer:

Part a)

$a_{hanger} = g - \frac{T}{m}$

Part b)

$a_{cart} = \frac{T}{M}$

Part c)

$a = \frac{mg}{M + m}$

Part d)

$a = 1.35 m/s^2$

Explanation:

Part a)

For hanger we know that it will have tension force upwards while it has downwards its weight so we will have

$mg - T = ma$

so we have

$a_{hanger} = g - \frac{T}{m}$

Part b)

now for car that is rolling on the floor the net force is given as

$F = Ma$

$T = Ma$

$a_{cart} = \frac{T}{M}$

Part c)

now we know that the cart and the hanger both are connected to each other

so they must have same acceleration

so we will have

$T = Ma$

$mg - Ma = ma$

$a = \frac{mg}{M + m}$

Part d)

now we know that

M = 2.40 kg

m = 0.50 kg

so we will have

$a = \frac{0.50(9.81)}{2.40 + 0.50}$

$a = 1.35 m/s^2$

6 0

3 years ago

Jason uses a lens with focal length of 10.0 cm as a magnifier by holding it right up to his eye. he is observing an object that

Svetlanka [38]

Answer:

3.5

Explanation:

The angular magnification, M = 1 + 25cm/f where f = focal length = 10.0 cm

M = 1 + 25cm/f

= 1 + 25cm/10.0 cm

= 1 + 2.5

= 3.5

7 0

3 years ago