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3 years ago

How much of the Moon is always illuminated one time? Explain your answer.

Physics

1 answer:

Natalija [7]3 years ago

6 0

Answer:

50% of it .

Explanation:

50% of it is illuminated by the Sun.

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With detailed explaniation

belka [17]

Ø=37°
Initial velocity=u=20m/s
g=10m/s²

$\\ \rm\Rrightarrow H_{max}=\dfrac{u^2sin^2\theta}{2g}$

$\\ \rm\Rrightarrow H_{max}=\dfrac{20^2(sin37)^2}{2(10)}$

$\\ \rm\Rrightarrow H_{max}=\dfrac{400sin^237}{20}$

$\\ \rm\Rrightarrow H_{max}=20sin^237$

$\\ \rm\Rrightarrow H_{max}=7.2m$

$\\ \rm\Rrightarrow R=\dfrac{u^2sin2\theta}{g}$

$\\ \rm\Rrightarrow R=\dfrac{20^2sin74}{10}$

$\\ \rm\Rrightarrow R=40sin74$

$\\ \rm\Rrightarrow R=38.5m$

$\\ \rm\Rrightarrow T=\dfrac{2usin\theta}{g}$

$\\ \rm\Rrightarrow T=\dfrac{2(20)sin37}{10}$

$\\ \rm\Rrightarrow T=4sin37$

$\\ \rm\Rrightarrow T=2.4s$

Now

$\\ \rm\Rrightarrow v=u-gt$

$\\ \rm\Rrightarrow v=20-10(2.4)$

$\\ \rm\Rrightarrow v=20-24$

$\\ \rm\Rrightarrow v=-4m/s$

4 0

2 years ago

The y-component of the force F which a person exerts on the handle of the box wrench is known to be 86 lb. Determine the x-compo

emmainna [20.7K]

Answer:

x-component of force is 38.18 lb where as magnitude of Force is 93.16

Explanation:

Fy of the force F exerted on the handle of the box wrench = 86 lb

Considering the triangle in Fig 1

magnitude of perpendicular = P = 12

magnitude of base = B = 5

using Pythagoras theorem

$H= \sqrt{P^{2} + B^{2}}$

$H= \sqrt{12^{2} + 5^{2}}$

$H=13\\\implies cos \theta = \frac{5}{13} \\\implies sin \theta = \frac{12}{13}\\$

y-component of force is given given as:

$86 = Fsin\theta\\F = 86 (\frac{13}{12})\\F = 93.16 lb\\F_{x} =F cos \theta\\F_{x} = 93.16 (\frac{5}{13})\\F_{x} =38.18 lb.$

5 0

3 years ago

A box exerts 10,000 Pa of pressure on the ground. If the box weighs 1000 N, how much area is in contact with the ground?

lara [203]

Pressure = (total force) / (Area)

10,000 Pa = (1,000 N) / (Area)

Multiply each side by (Area) :

(10,000 Pa) x (Area) = 1,000 N

Divide each side by (10,000 Pa) :

Area = (1,000 N) / (10,000 Pa)

4 0

3 years ago

• ALWAYS use significant figure rules. Remember that these rules apply to all numbers that are measurements.

nignag [31]

Answer:

45.6 m at $80.5^{\circ}$ south of west

Explanation:

Let's take the north-south direction as y-direction (with south being positive) and east-west direction as x-direction (with west being positive). Therefore, the two components of Cody's motion are:

- $d_y = 45.0 m$ (south)

- $d_x = 7.50 m$ (west)

Since they are perpendicular, the magnitude of the net displacement can be calculated by using Pythagorean's theorem:

$d=\sqrt{d_x^2+d_y^2}=\sqrt{7.50^2+45.0^2}=45.6 m$

The direction instead can be measured as follows:

$\theta = tan^{-1} (\frac{d_y}{d_x})=tan^{-1}(\frac{45.0}{7.50})=80.5^{\circ}$

And given the convention we have used, this angle is measured as south of west.

5 0

3 years ago

About how often does a 1-kilometer object strike the earth? about how often does a 1-kilometer object strike the earth? every ye

stiv31 [10]

The correct option is the second one, which is: Every million years.

The impact of a 1-kilometer object on our planet, would cause significant consequences. As the astronomers have found in other terrestrial bodies, this kind of impact creates largers craters on the surface.

5 0

3 years ago