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AfilCa [17]
3 years ago
8

Evaluate each geometric series described 1-4+16-64...., n=6

Mathematics
2 answers:
kykrilka [37]3 years ago
8 0

Answer:

-819

Step-by-step explanation:

This is Geometric series with first term as '1' and a common ratio of '-4' (-4÷1 = -4)

At n=5, the term is (-64×-4) = 256

At n=6, the term is (256×-4) = -1024

1-4+16-64+257-1024 = -819

xz_007 [3.2K]3 years ago
5 0

Answer:

- 819

Step-by-step explanation:

The sum to n terms of a geometric series is

S_{n} = \frac{a(r^n-1)}{r-1}

where a is the first term and r the common ratio

Here a = 1 and r = - 4 ÷ 1 = - 4, thus

S_{6} = \frac{1((-4)^6-1)}{-4-1} = \frac{4096-1}{-5} = \frac{4095}{-5} = - 819

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