Answer:
To establish this relationship we must examine the potentials that these forces create. The electrical potential is described by
Ve = k q / r
The potential for strong nuclear force is
Vn (r) = - gs / 4pir exp (-mrc / h)
Where gs is the stacking constant and r the distance between the nucleons,
We can compare these potentials where the force is derived from the relationship
E = -dU / dr
F = q E
Explanation:
The answer to this question is amplitude
Answer:
The resistance in first case is 12 Ω, power delivered is 12 W, and potential difference is 0.01 V
Explanation:
Given:
(A)
Current 
A
Voltage 
V
For finding the resistance,
12Ω
(B)
For finding power delivered,
Watt
(C)
For finding the potential difference,
V
Therefore, the resistance in first case is 12 Ω, power delivered is 12 W, and potential difference is 0.01 V
Answer:
A) μ = A.m²
B) z = 0.46m
Explanation:
A) Magnetic dipole moment of a coil is given by; μ = NIA
Where;
N is number of turns of coil
I is current in wire
A is area
We are given
N = 300 turns; I = 4A ; d =5cm = 0.05m
Area = πd²/4 = π(0.05)²/4 = 0.001963
So,
μ = 300 x 4 x 0.001963 = 2.36 A.m².
B) The magnetic field at a distance z along the coils perpendicular central axis is parallel to the axis and is given by;
B = (μ_o•μ)/(2π•z³)
Let's make z the subject ;
z = [(μ_o•μ)/(2π•B)] ^(⅓)
Where u_o is vacuum permiability with a value of 4π x 10^(-7) H
Also, B = 5 mT = 5 x 10^(-6) T
Thus,
z = [ (4π x 10^(-7)•2.36)/(2π•5 x 10^(-6))]^(⅓)
Solving this gives; z = 0.46m =
That would be only rotational motion
