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Levart [38]
2 years ago
10

Prove that s=ut+½at²​

Physics
1 answer:
katrin2010 [14]2 years ago
3 0

Explanation:

Distance travelled = Area under the line

= ut + ½ (v-u)t

Acceleration (a) = (v-u)/t and so (v-u) = at

Therefore,

Distance travelled (s) = ut + ½ (v-u)t = ut + ½ (at)t = ut + ½ at²

Thus,proved.

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Answer:

the correct one is B     ₊₁e

Explanation:

In the radioactive emission process there are three fundamental types, enision of alpha particles, emission of beta rays and emission of high energy photons.

In beta particle emission processes, a neutron decomposes, emitting an electron and an antineutrino, so the mass number of the nucleus does not change, but the atomic number increases by one unit.

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The second beta emission process if it describes the situation presented, when reviewing the answers the correct one is B

5 0
3 years ago
A plane flying against the wind covers the 900-kilometer distance between two aerodromes in 2 hours. The same plane flying with
Mashcka [7]

Answer:

The speed of the wind is 25 km/hr.

Explanation:

Let us call v_p the speed of the plane and v_w the speed of the wind. When the plane is flying against the wind, it covers the distance of 900-km in 2 hours (120 minutes); therefore;

(1). v_p - v_w = \dfrac{900km}{120min}

And when the plane is flying with the wind, it covers the same distance in 1 hour 48 minutes (108 minutes)

(2). v_p+v_w= \dfrac{900km}{108min}

From equation (1) we solve for v_p and get:

v_p = \dfrac{900km}{120min}+v_w,

and by putting this into equation (2) we get:

\dfrac{900km}{120min}+v_w+v_w= \dfrac{900km}{108min}

2v_w= \dfrac{900km}{108min}-\dfrac{900km}{120min}

2v_w = 8.3km/min - 7.5km/min

2v_w = 0.83km/min

v_w = 0.4165km/min

or in km/hr this is

\boxed{v_w= 25km/hr }

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Answer:

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Explanation:

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