Answer:
sphere #1 carries positive charge and #2 carries negative charge
This is because from the laws of static electricity, disconnecting the copper wire makes #1 to be positively charged and #2 to be negatively charged
 
        
             
        
        
        
Answer:
r2/r1 = 1.3
Explanation:
Electric field is given as:
E = kq/r²
At a distance r1,
226 = kq/(r1)² - - - - - - - - - - - - - (1)
At a distance r2,
134 = kq/(r2)² - - - - - - - - - - - - - (2)
From (1),
kq = 226 * (r1)²
From (2),
kq = 134 * (r2)²
Equating and then solving, 
134 * (r2)² = 226 * (r1)²
(r2)²/(r1)² = 226/134
(r2)²/(r1)² = 1.687
=> r2/r1 = 1.3
 
        
                    
             
        
        
        
Answer:
t = 1023.9 seconds
Explanation:
Given that,
The average velocity of a Mustang, v = 33m/s
Distance, d = 21 miles = 33789 m
Let the driver takes t seconds. So,
Speed = distance/time 

So, it will take 1023.9 seconds to complete the course.
 
        
             
        
        
        
Answer:
The distance on the screen between the first-order bright fringes  for each wavelength is 3.17 mm.
Explanation:
Given that,
Wavelength of red = 660 nm
Wavelength of blue = 470 nm
Separated d= 0.30 mm
Distance between screen and slits D= 5.0 m
We need to calculate the distance for red wavelength
Using formula for distance

Where, D = distance between screen and slits
d = separation of slits
Put the value into the formula


For blue wavelength,
Put the value into the formula again


We need to calculate the distance on the screen between the first-order bright fringes for each wavelength
Using formula for distance



Hence, The distance on the screen between the first-order bright fringes  for each wavelength is 3.17 mm.
 
        
             
        
        
        
Answer:
Tension=  (g=acceleration of gravity)
  (g=acceleration of gravity)
Explanation:
Given that,
A 5Kg and 10Kg are attached by a cable suspended over a pulley. 
As 10Kg > 5Kg , the 10 kg mass accelerates down and the 5kg mass accelerates up, let it be a. Let the tension in the cable be T.
So, the equations of motion are
 
 

Now adding them we get,


Substituting them back in the equation we get,

