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Lina20 [59]
3 years ago
9

How do determine which is Y2, Y1, X2, and X1 on a graph. And how do find rise over run.

Physics
1 answer:
fredd [130]3 years ago
7 0
One point will be X1,Y1 and the other will be X2,Y2. It does not matter which is which except that X1 and Y1 have to be the same point and X2 and Y2 have to be the same point. For example, let's say you were given (2,3) and (6,8). No matter which point is X1,Y1 and the other is X2,Y2, the slope will still be 5/4. 

The rise is the change in y from one point to the other. The run would be the change in x from one point to the other.
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Answer:

1327 kg

Explanation:

So the net force exerted on the wagon would be the sum of forces from 2 horses subtracted by friction force

F = 1000 + 800 - 75 = 1725 N

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m = F / a = 1725 / 1.3 \approx 1327 kg

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A 1 200-kg car traveling initially at vCi 5 25.0 m/s in an easterly direction crashes into the back of a 9 000-kg truck moving i
sukhopar [10]

Answer:

The velocity of the truck after the collision is 20.93 m/s

Explanation:

It is given that,

Mass of car, m₁ = 1200 kg

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Mass of truck, m₂ = 9000 kg

Initial velocity of the truck, v_{Ti}=20\ m/s

After the collision, velocity of the car, v_{Cf}=18\ m/s

Let v is the velocity of the truck immediately after the collision. The momentum of the system remains conversed.

initial\ momentum=final\ momentum

1200\ kg\times 25\ m/s+9000\ kg\times 20\ m/s=1200\ kg\times 18+9000\ kg\times v

210000-21600=9000\ kg\times v

v=20.93\ m/s

So, the velocity of the truck after the collision is 20.93 m/s. Hence, this is the required solution.

8 0
3 years ago
An iron sphere of radius 0.18m has mass 190 kg. Calculate the density of the iron
Slav-nsk [51]
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Volume:-

\\ \sf\rightarrowtail \dfrac{4}{3}\pi r^3

\\ \sf\rightarrowtail \dfrac{4}{3}\pi (0.18)^3

\\ \sf\rightarrowtail \dfrac{4}{3}\pi (0.005832)

\\ \sf\rightarrowtail 0.024m^3

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Density:-

\\ \sf\rightarrowtail \dfrac{Mass}{Volume}

\\ \sf\rightarrowtail \dfrac{190}{0.024}

\\ \sf\rightarrowtail 7916.67kg/m^3

8 0
2 years ago
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