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alexandr402 [8]
3 years ago
5

In the cores of extremely hot red giants, nuclear reactions convert helium to _____. hydrogen carbon lead argon

Chemistry
2 answers:
Tpy6a [65]3 years ago
4 0

Red giants produce "metals", i.e., heavier elements.

The first step is helium conversion into

<span>carbon</span>

Arturiano [62]3 years ago
4 0
<h3><u>Answer;</u></h3>

Carbon

<h3><u>Explanation;</u></h3>

In the cores of extremely hot red giants, nuclear reactions convert helium to <u>carbon</u>.

  • A red giant star is a dying star in the last stages of stellar evolution. In the main sequence stage stars convert hydrogen into helium through nuclear fusion.
  • As stars in the main sequence stage slowly converts their core from hydrogen to helium the fusion continues to create a shell and soon the Helium core begins to shrink, and visible of the star change. The star becomes a red giant.
  • <em><u>In the red giant core the nuclear reactions convert helium into carbon. This happens when the temperature reaches 100 million K, and the nuclear fusion of He to Carbon begins, creating carbon and releasing energy.</u></em>
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Explain how you would decide which represents a greater mass: 3.25 x 1022 atoms of Ca or 2.45 grams of Mg?
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Answer:

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Explanation:

The amount of matter is measured in grams. Thus, you need to convert the number of atoms of Ca (calcium) into mass to compare with 2.45 grams of Mg.

To convert the atoms of calcium into mass, you divide by Avogadro's number, to obtain the number of moles of atoms, and then divide by the atomic mass of calcium.

<u />

<u>1. Number of moles, n</u>

      n=\dfrac{\text{number of atoms}}{\text{Avogadro's number}}\\ \\ \\ n=\dfrac{3.25\times 10^{22}}{6.022\times 10^{23}}=0.053969mol

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<u>2. Mass</u>

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Calculate the number of moles of a gas that is present in a 7.55 L container at 45°C, if the gas exerts a pressure of 725mm Hg.
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To calculate the number of moles of gas, we use the equation given by ideal gas:

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R = Gas constant = 62.3637\text{ L.mmHg }mol^{-1}K^{-1}

T = Temperature of the gas = 45^oC=(45+273)K=318K

Putting values in above equation, we get:

725mmHg\times 7.55L=n\times 62.3637\text{ L.mmHg }mol^{-1}K^{-1}\times 318K\\\\n=0.276mol

Hence, the number of moles of gas present is 0.276 moles

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