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alexandr402 [8]
2 years ago
5

In the cores of extremely hot red giants, nuclear reactions convert helium to _____. hydrogen carbon lead argon

Chemistry
2 answers:
Tpy6a [65]2 years ago
4 0

Red giants produce "metals", i.e., heavier elements.

The first step is helium conversion into

<span>carbon</span>

Arturiano [62]2 years ago
4 0
<h3><u>Answer;</u></h3>

Carbon

<h3><u>Explanation;</u></h3>

In the cores of extremely hot red giants, nuclear reactions convert helium to <u>carbon</u>.

  • A red giant star is a dying star in the last stages of stellar evolution. In the main sequence stage stars convert hydrogen into helium through nuclear fusion.
  • As stars in the main sequence stage slowly converts their core from hydrogen to helium the fusion continues to create a shell and soon the Helium core begins to shrink, and visible of the star change. The star becomes a red giant.
  • <em><u>In the red giant core the nuclear reactions convert helium into carbon. This happens when the temperature reaches 100 million K, and the nuclear fusion of He to Carbon begins, creating carbon and releasing energy.</u></em>
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1) 0.3g Mg

2)0.5g MgO

3)0.2g O

4)0.01mol Mg & 0.01mol O

5)0.01mol MgO

6) Empirical formula MgO

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The mass og Mg is obtained by substracting 24.36g from 24.66g:

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The ignition of Mg means that it's reacting with oxygen to form an oxide. The increase in the crucible mass after the Mg ignition is due to the addition of oxygen. However, the addition of few drops of water produces a new compound: a hydroxide. According to the oxidation state og Mg (2+), the only magnesium oxide possible is MgO. It happens because the oxidation state of oxygen in oxides is 2-. Which means that just one oxygen atom is required to electrically neutralize one magnesium atom.

We can use a conversion factor to know how much MgO is made from from 0.3 g of Mg:

0.3g Mg*\frac{16gO}{24.3gMg}= 0.2g O

Thereby the mass of the oxide is 0.2g O + 0.3g Mg = 0.5g MgO

We convert the mass of oxygen and magnesium to the respective amounts in moles by using conversion factors:

0.2g O*\frac{1 mol O}{16g O}= 0.01mol O

0.3g Mg*\frac{1mol Mg}{24.3g Mg}= 0.01mol Mg

The moles of MgO can be obtained from:

0.5g MgO*\frac{1mol MgO}{40.3g MgO}= 0.01mol MgO

To obtain the empirical formula, the amount fo moles of each elements must be divided by the smallest one, in this case, 0.01.

The result for both number of  Mg atoms and O atoms is 1. This can be interpreted to mean that there is a Mg atom for each O atom forming the  formula unit of the compound.

The step when water is added to the compound resulting after heating does not affect the calculations necessary for the magnesium oxide.

4 0
2 years ago
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