Answer: See the explanation below.
Explanation: For this assignment, I chose to display how eclipses are created.
My model was made utilizing a 3D displaying device program for all intents and purposes. The items utilized are three models I made for this presentation, Earth, the moon, and the sun. These three models will be utilized for the showcase.
The light that shines from the sun would create a shadow on the moon. The moon would then catch the light that should've arrived on Earth, making the shadow we call an eclipse. Earth gets a shadow of the moon and the remainder of Earth is lit up from the rest of the light, making an eclipse.
The individual I demonstrated my project to was [<em>Someone you know</em>], [<em>Pronoun</em>] said it precisely took after the occasion of an eclipse. The light from the sun being shined on to the moon rather than the Earth, creating the shadow we call an eclipse.
1) 3 miles/Hour
The speed is defined as the distance covered divided by the time taken:
![v=\frac{d}{t}](https://tex.z-dn.net/?f=v%3D%5Cfrac%7Bd%7D%7Bt%7D)
where
d = 1.5 mi is the distance
t = 0.5 h is the time taken
Substituting,
![v=\frac{1.5}{0.5}=3 mi/h](https://tex.z-dn.net/?f=v%3D%5Cfrac%7B1.5%7D%7B0.5%7D%3D3%20mi%2Fh)
2) 1.34 m/s south
Velocity, instead, is a vector, so it has both a magnitude and a direction. We have:
is the displacement in meters
is the time taken in seconds
Substituting,
![v=\frac{2414 m}{1800 s}=1.34 m/s](https://tex.z-dn.net/?f=v%3D%5Cfrac%7B2414%20m%7D%7B1800%20s%7D%3D1.34%20m%2Fs)
And the direction of the velocity is the same as the displacement, so it is south.
Answer:
The work done by gravity is ![4.975 \: Joules](https://tex.z-dn.net/?f=4.975%20%5C%3A%20Joules)
Explanation:
The data given in the question is :
Mass is ![0.245 kg](https://tex.z-dn.net/?f=0.245%20kg)
Height from ground is ![2.07 m](https://tex.z-dn.net/?f=2.07%20m)
As we know , the work done is state function , it depends on initial and final position not on the path followed.
So, work done by gravity = change in potential energy
Work done = Initial potential energy - final potential energy
Insert values from question
Work done = ![mass \times gravity \times (change \: in \: height)](https://tex.z-dn.net/?f=mass%20%5Ctimes%20gravity%20%5Ctimes%20%28change%20%5C%3A%20in%20%5C%3A%20height%29)
Work done = ![0.245 kg \times 9.81 m/s^{2} \times 2.07 m](https://tex.z-dn.net/?f=0.245%20kg%20%5Ctimes%209.81%20m%2Fs%5E%7B2%7D%20%5Ctimes%202.07%20m)
So, work done = ![4.975 Joules](https://tex.z-dn.net/?f=4.975%20Joules)
Hence the work done by gravity is ![4.975 \: Joules](https://tex.z-dn.net/?f=4.975%20%5C%3A%20Joules)
Answer:
False
Explanation:
The given statement "Two objects must be in contact for them to exert a force on each other" is not true as there are many types of forces that doesn't require being in contact for exerting a force.
One such example is the gravitational force acting between two bodies. Gravitational force is the force of pull with which a body pulls another body without being in contact.
For two bodies of masses 'M' and 'm' separated at a distance of 'R', the gravitational force is given as:
![Force=\frac{GMm}{R^2}\\Where,G\to \textrm{Universal Gravitational constant}](https://tex.z-dn.net/?f=Force%3D%5Cfrac%7BGMm%7D%7BR%5E2%7D%5C%5CWhere%2CG%5Cto%20%5Ctextrm%7BUniversal%20Gravitational%20constant%7D)
The gravitational force acts always act between bodies that have mass. The bodies are not in contact yet experience force.
Therefore, the given statement is false.