Question

In the deep ocean, a water wave with wavelength 95 m travels at 12 m/s. Suppose a small boat is at the crest of this wave, 1.2 m above the equilibrium position. What will be the vertical position of the boat 5.0 s later?

Answer 1

Answer:

the vertical position is 1.1971m

Explanation:

Recall that

$y = 1.2 * cos (\frac{2*\pi * distance travelled}{wavelenght})$

recall that $v = \frac{distance}{time}$

$thus; distance = v* t$

this implies that distance = 12 * 5.0

                                          =  60

therefore;  $y = 1.2 cos \frac{2*3.142*60}{95}$

                  y = 1.1971m

the