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otez555 [7]
2 years ago
11

Calculate the density of a 20.015 g object that occupies 5.44 cm3 .

Chemistry
2 answers:
rjkz [21]2 years ago
7 0

Answer:

3.679

Explanation:

the density of a 20.015 g object that occupies 5.44 cm3 is 3.679

Scilla [17]2 years ago
5 0

Answer:

density =  \frac{mass}{volume}  \\  \\ density =  \frac{20.015}{5.44}  \\  \\ { \boxed{ \boxed{density = 3.679 \: g {cm}^{ - 3} }}}

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1.137448506 mol moles of chlorine gas would occupy a volume of 35.5 L at a pressure of 100.0 kPa and a temperature of 100.0 degrees Celsius.

<h3>What is an ideal gas equation?</h3>

The ideal gas equation, pV = nRT, is an equation used to calculate either the pressure, volume, temperature or number of moles of a gas. The terms are: p = pressure, in pascals (Pa). V = volume, in m^3.

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Substituting the values in the equation.

n= \frac{\;0,98 \;atm \;X \;35,5 \;L }{\;0,082\;atm / \;K mol \;X \;373 K}

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Learn more about ideal gas here:

brainly.com/question/16552394

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2 years ago
A pH scale has how many sections on it?
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3 years ago
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