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otez555 [7]
2 years ago
11

Calculate the density of a 20.015 g object that occupies 5.44 cm3 .

Chemistry
2 answers:
rjkz [21]2 years ago
7 0

Answer:

3.679

Explanation:

the density of a 20.015 g object that occupies 5.44 cm3 is 3.679

Scilla [17]2 years ago
5 0

Answer:

density =  \frac{mass}{volume}  \\  \\ density =  \frac{20.015}{5.44}  \\  \\ { \boxed{ \boxed{density = 3.679 \: g {cm}^{ - 3} }}}

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marishachu [46]

Answer:

0.464 L

Explanation:

Molarity (M) = number moles (n) ÷ volume (V)

According to the information given in this question:

number of moles (n) = 4.36 moles

Molarity = 9.4M

Volume = ?

Using M = n/V

9.4 = 4.36/V

9.4V = 4.36

V = 4.36/9.4

V = 0.464 L

Hence, 0.464L of water are needed the volume of water.

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If 2.9g of water is heated from 23.9C to 98.9C, how much heat (in calories) was added to the water?
tensa zangetsu [6.8K]

Answer:

Explanation:

we know that

ΔH=m C ΔT

where ΔH is the change in enthalpy (j)

m is the mass of the given substance which is water in this case

ΔT IS the change in temperature and c is the specific heat constant  

we know that given mass=2.9 g

ΔT=T2-T1 =98.9 °C-23.9°C=75°C

specific heat constant for water is 4.18 j/g°C

therefore ΔH=2.9 g*4.18 j/g°C*75°C

ΔH=909.15 j

7 0
3 years ago
Why does it matter if atoms are divisible ???
Andreyy89

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They certainly are not that important to our lives, but it’s good to know :)

5 0
2 years ago
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