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Andrews [41]
3 years ago
5

Pentaoxygen monochloride formula​

Chemistry
1 answer:
kicyunya [14]3 years ago
6 0

Answer:

Explanation:

O5Cl

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Air at 7S°F and14.6 though a cfm(cubic ft per minute) and the The flow rate is 48000 psia flows though a rectangular duct of Ix2
IgorLugansk [536]

Explanation:

The given data is as follows.

Air is at 75^{o}F and 14.6 psia.

\varepsilon = 0.00015 ft,     Flow rate, (Q) = 48000 ft^{3}/m

(a)  Formula to calculate hydraulic radius (r_{H}) is as follows.

              r_{H} = \frac{\text{free flow area}}{\text{wet perimeter}}

                          = \frac{2 \times 1}{2(1) + 2(2)}

                          = \frac{1}{3} ft

Formula for equivalent diameter is as follows.

                     D_{eq} = 4 \times r_{H}

                                    = 4 \times \frac{1}{3} ft  

                                    = \frac{4}{3} ft

(b)    Formula for velocity floe is as follows.

                         Q = VA

                     V = \frac{Q}{A}

                        = \frac{48000}{2 \times 1} ft/min

                        = 24000 ft/min

(c)   Formula to calculate Reynold's number is as follows.

         R_{e} = \frac{D \times V \times \rho}{\mu}

                   = \frac{\frac{4}{3} \times 24000 \times 0.0744}{0.0443}  (as \rho = 0.0744 lb/ft^{3} and \mu = 0.0443 lb/ft. hr)

                   = 53742.66 hr/min  

As 1 hr = 10 min. So, 53742.66 hr/min \times \frac{60 min}{1 hr}

                            = 3224559.6

(d)   Formula to calculate pressure drop (\Delta P) is as follows.

              \frac{\Delta P}{L} = \frac{4f \rho V^{2}}{2Dg_{c}}

Putting the given values into the above formula as follows.

               \frac{\Delta P}{L} = \frac{4f \rho V^{2}}{2Dg_{c}}

                      = \frac{4 \times 0.00015 \times 100 \times 0.0744 \times (24000)^{2}}{2 \times \frac{4}{3} \times {4}{3}}

                      = 6.238 lb/ft^{2}

5 0
3 years ago
Select the correct answer.
vitfil [10]

Answer:

The answer is B

Explanation:

6 0
3 years ago
Read 2 more answers
The atmosphere of the planet Mars is 95.3% carbon dioxide, 2.6% nitrogen, 1.9% argon, with the remaining fraction being traces o
kodGreya [7K]

Answer:

Mean Partial pressure of Nitrogen in Mars' atmosphere = 15.86 Pa

Explanation:

According to Dalton's law of Partial Pressure, the total pressure exerted by a mixture of ideal gases (that do not react together) is the sum of the partial pressures of the individual gases that make up the mixture. It goes further to explain that the partial pressure of a gas in a mixture of gases is equal to its mole fraction of that gas multipled by the total pressure exerted by the mixture of gases.

Total Pressure exerted by the mixture of gases in the atmosphere on Mars = Mean atmospheric pressure on Mars = 610 Pa

Partial pressure of Nitrogen = (mole fraction or mole percentage of Nitrogen in the atmosphere) × (total pressure exerted by all the gases in the atmosphere)

Mole percentage of Nitrogen in the atmosphere of Mars = 2.6%

Partial pressure of Nitrogen = 2.6% × 610 = 15.86 Pa

Mean Partial pressure of Nitrogen in Mars' atmosphere = 15.86 Pa

Hope this Helps!!!

3 0
3 years ago
Which of the following is the smaller atom: magnesium or chlorine?
Aleks04 [339]

Answer:

Chlorine atoms are smaller

Explanation:

Magnesium have more electrons than chlorine.

3 0
3 years ago
Read 2 more answers
6. El oxígeno gaseoso se calienta a presión constate de 50 °C a 300 K. Se conoce que inicialmente el volumen del sistema era de
frez [133]

Answer:

El volumen final del sistema es 1.2L

Explanation:

La ley de Charles establece que el incremento de la temperatura de un gas produce un incremento en el volumen directamente proporcional cuando la presión permanece constante. La ecuación es:

V₁/T₁ = V₂/T₂

<em>Donde V es volumen y T temperatura absoluta de un gas en 1, el estado inicial y 2, su estado final.</em>

<em />

Reemplazando:

V₁ = 1.3L

T₁ = 50°C + 273.15K = 323.15K

V₂ = Incógnita

T₂ = 300K

1.3L/323.15K = V₂/300K

1.2L = V₂

<h3>El volumen final del sistema es 1.2L</h3>
3 0
3 years ago
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