Pentaoxygen monochloride formula

Will mark Brainlest ( molecular weight of ammonium sulphate) step by step

Bond [772]

Answer:

132 amu

Explanation:

ammonium sulphate is $(NH_4)_{2} SO_4$

to calculate molecular weight we need

atomic weight of the element of the compound

here ammonium sulphate is formed by two elements

2 nitrogen , 8 hydrogen , 1 sulphur amd 4 oxygen

atonomic number of nirogen is 14 , hydrogen is 1 , sulphur has 32 and oxygen has 16

so lets calculate molecular weight of ammonium sulphate

2*14 + 8*1 + 1*32 + 4*16

28 + 8 + 32 + 64

132 amu

3 0

2 years ago

Natural resource management and economics focus mostly on which type of externality?

katovenus [111]

negative

Explanation:

hope this helps

6 0

2 years ago

What is the maximum number of grams of N-acetyl-p-toluidine can be prepared from 70. milliliters of 0.167 M p-toluidine hydrochl

Genrish500 [490]

Answer: The maximum amount of N-acetyl-p-toluidine that can be prepared is 1.7 grams.

Explanation:

To calculate the number of moles for given molarity, we use the equation:

$\text{Molarity of the solution}=\frac{\text{Moles of solute}\times 1000}{\text{Volume of solution (in mL)}}$

Molarity of p-toluidine hydrochloride solution = 0.167 M

Volume of solution = 70. mL

Putting values in above equation, we get:

$0.167M=\frac{\text{Moles of p-toluidine hydrochloride}\times 1000}{70}\\\\\text{Moles of p-toluidine hydrochloride}=\frac{0.167\times 70}{1000}=0.0117mol$

The chemical equation for the reaction of p-toluidine hydrochloride and acetic anhydride follows:

$\text{p-toluidine hydrochloride}+\text{Acetic anhydride}\rightarrow \text{N-acetyl-p-toluidine}$

By Stoichiometry of the reaction:

1 mole of p-toluidine hydrochloride produces 1 mole of N-acetyl-p-toluidine

So, 0.0117 moles of p-toluidine hydrochloride will produce = $\frac{1}{1}\times 0.0117=0.0117mol$ of N-acetyl-p-toluidine

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$

Molar mass of N-acetyl-p-toluidine = 149.2 g/mol

Moles of N-acetyl-p-toluidine = 0.0117 moles

Putting values in equation 1, we get:

$0.0117mol=\frac{\text{Mass of N-acetyl-p-toluidine}}{149.2g/mol}\\\\\text{Mass of N-acetyl-p-toluidine}=(0.0117g/mol\times 149.2)=1.7g$

Hence, the maximum amount of N-acetyl-p-toluidine that can be prepared is 1.7 grams.

6 0

3 years ago

Is phosphorous an atom, element, or compound

Marrrta [24]

Answer:

its element

Explanation:

7 0

2 years ago

Read 2 more answers

Characterize EACH of the three given statements as being TRUE or FALSE and then indicate the collective true-false status of the

Alinara [238K]

Answer:

Electron loss is always associated with an increase in oxidation number- True

An exothermic reaction occurs when the energy required to break bonds in reactants is less than the energy released by bond formation in the products. True

The concentrations of pure liquids and pure solids are never included in an equilibrium constant expression because such concentrations never change. True

Explanation:

Oxidation implies loss of electrons. When a specie looses electrons, its oxidation number increases. For instance; Fe(s) -----> Fe^2+(aq) + 2e implies an increase in oxidation number of Fe from 0 to +2.

In an exothermic reaction, the energy required to break the bonds in the reactants is less than the energy released when new bonds form in the products.

We do not include the concentrations of pure liquids and pure solids in the equilibrium constant expression because the concentration of these do not change significantly throughout the reaction.

3 0

2 years ago

Pentaoxygen monochloride formula​

Pentaoxygen monochloride formula