Answer:
Yes
Explanation:
If the Ajax representative fails to correct the previous statement this can cause misrepresentation.
The question is not complete. We are supposed to find the average value of v_o.
Answer:
v_o,avg = 0.441V
Explanation:
Let t1 and t2 be the start and stop times of the output waveforms. Thus, from the diagram i attached, using similar triangles, we have;
3/(T/4) = 0.7/t1
So, 12/T = 0.7/t1
So, t1 = 0.7T/12
t1 = 0.0583 T
Also, from symmetry of triangles,
t2 = T/2 - t1
So, t2 = T/2 - 0.0583 T
t2 = 0.4417T
Average of voltage output is;
v_o,avg = (1/T) x Area under small triangle
v_o,avg = (1/T) x (3 - 0.7) x (T/4 - t1)
v_o,avg = (1/T) x (2.3) x (T/4 - 0.0583 T)
v_o,avg = (1/T) x 2.3 x 0.1917T
T will cancel out to give;
v_o,avg = 0.441V
The correct answers are B & C; Chatter Groups and Similar opportunities.
Further Explanation:
Sales representatives can use chatter groups and other similar opportunities to their advantage. This can help them to understand and manage their products that are in direct competition with competitors.
A chatter group can be used to share ideas both privately and publicly. These groups can have more than 30,000 people or just 3 people, it depends on how many are interested in the topic or product. The groups can be made unlisted and by invite only and then you can see with whom you are talking to. Nonmembers can view anything written in the public and archived groups. This is a great way to see how your peers are doing with their product.
Learn more about chatter groups at brainly.com/question/4489111
#LearnwithBrainly
Answer:
a) 512.5 KW/m2
b) 40.75 KW/m2
c) 2 KW/m2
Explanation:
Given data;
T_2 = 325 K
T_1 = 275 K
dx = 0.20 mm
a) for aluminium K = 205 W/m k
heat flux 

= 512.5 KW/m2
b) for AISI 316 stainless steel
k = 16.3 W/ m k
heat flux 

= 40.75 KW/m2
C) for Concrete
k = 0.8 W/ m k
heat flux 

= 2 KW/m2