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MrMuchimi
3 years ago
13

Sometimes, steel studs may not be used on outside walls because they are?

Engineering
1 answer:
Helen [10]3 years ago
6 0

Answer:

We can describe 15×-10 as an expression. we would describe 6×-2< 35 as an...

Explanation:

We can describe 15×-10 as an expression. we would describe 6×-2< 35 as an...

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(i) what assumptions about the relationship between the inputs and output are inherent in this specification? do scatter plots s
olasank [31]

A problem that will be handled by a procedure is described by an input-output specification.

<h3>What is input and output specification?</h3>
  • An input-output specification outlines the issue that a procedure will try to solve. The input part and the output part are its two components.
  • The input component outlines the kind of data object that should be provided for each actual argument as well as any presumptions that the process might make.
  • A technical specification known as an output specification defines the project scope primarily through performance-based requirements.
  • It is used to assess technical compliance and serves as the technical cornerstone of both the procurement and delivery phases.
  • Known as classical specifications, they outline the precise services to be provided, sometimes in great detail, along with the standard you must meet and the approach you must take to meet the standard.

To Learn more About input-output specification Refer To:

brainly.com/question/25265909

#SPJ4

5 0
1 year ago
The diffusion coefficients for species A in metal B are given at two temperatures:
Kruka [31]

Answer:

a) 149 kJ/mol, b) 6.11*10^-11 m^2/s ,c) 2.76*10^-16 m^2/s

Explanation:

Diffusion is governed by Arrhenius equation

D = D_0e^{\frac{-Q_d}{RT} }

I will be using R in the equation instead of k_b as the problem asks for molar activation energy

I will be using

R = 8.314\ J/mol*K

and

°C + 273 = K

here, adjust your precision as neccessary

Since we got 2 difusion coefficients at 2 temperatures alredy, we can simply turn these into 2 linear equations to solve for a) and b) simply by taking logarithm

So:

ln(6.69*10^{-17})=ln(D_0) -\frac{Q_d}{R*(1030+273)}

and

ln(6.56*10^{-16}) = ln(D_0) -\frac{Q_d}{R*(1290+273)}

You might notice that these equations have the form of  

d=y-ax

You can solve this equation system easily using calculator, and you will eventually get

D_0 =6.11*10^{-11}\ m^2/s\\ Q_d=1.49 *10^3\ J/mol

After you got those 2 parameters, the rest is easy, you can just plug them all   including the given temperature of 1180°C into the Arrhenius equation

6.11*10^{-11}e^{\frac{149\ 000}{8.143*(1180+273)}

And you should get D = 2.76*10^-16 m^/s as an answer for c)

5 0
3 years ago
Whatever they said bbbbbbbbbbbbbbbbbb
solong [7]

Answer:

yh and I said aaaaaaaaaaaa

Explanation:

7 0
3 years ago
Read 2 more answers
Where is the Volkswagen super factory located? how is this locate relevant to us?​
Blizzard [7]
It’s in Wolfsburg Germany
4 0
3 years ago
The following laboratory test results for Atterberg limits and sieve-analysis were obtained for an inorganic soil. [6 points] Si
alexira [117]

Answer: hello the complete question is attached below

answer:

A) Group symbol = SW

B) Group name = well graded sand , fine to coarse sand

C) It is not a clean sand given that ≤ 50% particles are retained on No 200

Explanation:

<u>A) Classifying the soil according to USCS system</u>

 ( using 2nd image attached below )

<em>description of sand</em> :

The soil is a coarse sand since  ≤ 50% particles are retained on No 200 sieve, also

The soil is a sand given that more than 50% particles passed from No 4 sieve

The soil can be a clean sand given that fines ≤ 12%

The soil can be said to be a well graded sand because the percentage of particles passing through decreases gradually over time

Group symbol as per the 2nd image attached below = SW

B) Group name = well graded sand , fine to coarse sand

C) It is not a clean sand given that ≤ 50% particles are retained on No 200

5 0
3 years ago
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