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swat32
3 years ago
11

A cylinder of oxygen gas contains 2.80 mol of 02. If the volume of the cylinder is 8.58 L, what is the pressure of the 02 if the

gas temperature is 294 K.
Chemistry
2 answers:
Anni [7]3 years ago
6 0

Answer:

pressure of the oxygen gas is 7.88atm

Explanation:

Moles of oxygen in cylinder  =  2.80 mol

volume=8.58L

temperature=294K

molar gas constant(R)= 0.0821 L atm / (mol K)

The pressure is calculated using ideal gas law:

PV = nRT

making Pressure subject of the formula

P = nRT /V

  = 2.80× 0.0821 ×294  /8.58 L

P = 7.88 atm

OlgaM077 [116]3 years ago
3 0

Answer:

7.88 atm

Explanation:

This question is a very straight forward Question, we have given almost all the parameters needed to solve the question. The parameters given in the question are: Number of moles of oxygen gas = 2.80 mol, the volume of the cylinder= 8.58 L, pressure of the 02 = ???( not given) and the gas temperature = 294 K.

We are going to use the formula for the ideal gas law below to solve this question:

PV = nRT.

Where P = pressure, V = volume , n= number of moles, R= gas constant and T= temperature.

nRT/ V= P.

P= 2.80 × 0.0821 × 294/ 8.58.

P= 67.58472÷ 8.58.

P= 7.87700699300699300.

P= 7.88 atm.

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How many moles are in 7.46 x 1025 particles of iron
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Answer:

1 mole of iron =6.023×10^23 particles

1 particles of iron=1/6.023×10^23 mole

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=1.238×10^48 mole is a required answer.

4 0
2 years ago
An atom of 70kr has a mass of 69. 955264 amu. mass of1h atom = 1. 007825 amu mass of a neutron = 1. 008665 amu. calculate the bi
Leno4ka [110]

The binding energy in MeV per atom is - 63284.56 Mev.

The amount of energy needed to detach a particle from a system of particles or to disperse every particle in the system is known as the binding energy. Subatomic particles in atomic nuclei, electrons attached to atom's nuclei, and atoms and ions bonded together in crystals are three examples of where binding energy is very relevant.

If we have a nucleus with Z protons and N neutrons and mass MA, where A = Z + N then its binding energy in MeV is given by: Eb(MeV) = (Zmp + Nmn - MA) x 931.494 MeV/u

Mass of atom = 69.955264 amu

Mass of proton = 1.007825 amu

Mass of neutron = 1.008665 amu

Binding energy, Mev = (Zmp + Nmn - M) × 931.494MeV/u

                                    = ( 1.007825 + 1.008665 -  69.955264) × 931.494

                                    = - 67.938774 × 931.494

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Therefore, the binding energy in MeV per atom is - 63284.56 Mev.

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3 0
1 year ago
How many particles are present in 12.47 grams of NaCl
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Answer:

1.26*10²³ particles are present in 12.47 grams of NaCl

Explanation:

Avogadro's Number or Avogadro's Constant is called the number of particles that make up a substance (usually atoms or molecules) and that can be found in the amount of one mole of said substance. Its value is 6.023 * 10²³ particles per mole. The Avogadro number applies to any substance.

So, first of all you must know the amount of moles that represent 12.47 grams of NaCl. For that it is necessary to know the molar mass.

You know:

  • Na: 23 g/mole
  • Cl: 35.45 g/mole

So the molar mass of NaCl is: 23 g/mole + 35.45 g/mole= 58.45 g/mole

Now you apply a rule of three as follows: if 58.45 grams are present in 1 mole of NaCl, 12.47 grams in how many moles will they be?

moles=\frac{12.47 grams*1 mole}{58.45 grams}

moles= 0.21

You apply a rule of three again, knowing Avogadro's number: if in 1 mole of NaCl there are 6,023 * 10²³ particles, in 0.21 moles how many particles are there?

number of particles=\frac{0.21 moles*6.023*10^{23} }{1 mole}

number of particles= 1.26*10²³

<u><em>1.26*10²³ particles are present in 12.47 grams of NaCl</em></u>

<u><em></em></u>

5 0
3 years ago
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Lelu [443]

Answer: Atom/element

Explanation: Since matter cannot be created or destroyed, the number of atoms has to be equal on both sides of the equation.

4 0
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