How many mole ratios can be written for a chemical reaction involving 3 substances

2 answers:

7 0

There can be three mole ratios that can be written involving three substances.It depends on the constant of your reactant to your product. It also depends on the asked mole ratio. But the maximum would be 3 mole ratios because you have 3 substances in your reaction.

Stolb23 [73]3 years ago

4 0

Answer : 3 substance will have 3 mole ratios to be written for a chemical reaction.

Explanation : The mole ratio can be defined as the ratio between the amounts in moles of any two or more compounds involved in a chemical reaction.

It can be determined by comparing the coefficients the formulas of a balanced chemical equation. It is also known as the molar ratio or mole-to-mole ratio.

Hence, when 3 substances are involved in a chemical reaction 3 mole ratios can be written for it.

You might be interested in

HELPPPPP ME <br><br>PLISSSSS

Talja [164]

Answer:

pH value of a solution depends on the concentration of hydrogen ions

(pH = -log[H+(aq)].

Hydrochloric acid is a strong acid, while ethanoic acid is a weak acid. Strong acids ionize completely in water (to give ions which includes H+(aq)), while weak acids only ionize partially in water.

Therefore, even if both hydrochloric acid and ethanoic acid are monobasic acids (each molecule can ionize completely to give 1 hydrogen ion), since hydrochloric acid ionizes completely in water and ethanoic acid does not ionize completely, the concentration of hydrogen ions in hydrochloric acid is higher than that of ethanoic acid, leading to a lower pH value for hydrochloric acid, while higher for ethanoic acid.

8 0

3 years ago

A 0.89% (w/v) sodium chloride solution is referred to as physiological saline solution because it has the same concentration of

maks197457 [2]

1) 0.89% m/v = 0.89 grams of NaCl / 100 ml of solution

=> 8.9 grams of NaCl in 1000 ml of solution = 8.9 grams of NaCl in 1 liter of solution

2) Molarity = M = number of moles of solute / liters of solution

=> calculate the number of moles of 8.9 grams of NaCl

3) molar mass of NaCl = 23.0 g /mol + 35.5 g/mol = 58.5 g / mol

4) number of moles of NaCl = mass / molar mass = 8.9 g / 58.5 g / mol = 0.152 mol

5) M = 0.152 mol NaCl / 1 liter solution = 0.152 M

Answer: 0.152 M

4 0

2 years ago

For this reaction: 4 Al + 3O2 = 2 Al2O3

MariettaO [177]

0.347 mols, working out shown on photo