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shusha [124]
3 years ago
13

How many mole ratios can be written for a chemical reaction involving 3 substances

Chemistry
2 answers:
Anika [276]3 years ago
7 0
There can be three mole ratios that can be written involving three substances.It depends on the constant of your reactant to your product. It also depends on the asked mole ratio. But the maximum would be 3 mole ratios because you have 3 substances in your reaction.
Stolb23 [73]3 years ago
4 0

Answer : 3 substance will have 3 mole ratios to be written for a chemical reaction.

Explanation : The mole ratio can be defined as ​the ratio between the amounts in moles of any two or more compounds involved in a chemical reaction.

It can be determined by comparing the coefficients the formulas of a balanced chemical equation. It is also known as the molar ratio or mole-to-mole ratio.

Hence, when 3 substances are involved in a chemical reaction 3 mole ratios can be written for it.

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2.96804 moles that’s the answer. hope it helped
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Use the periodic table to identify the noble gas that would be included in the noble-gas notation for each of the following elem
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Substrate: N-benzoyl-L-tyrosine ethyl ester (BTEE) 0.001M in 50% aqueous
andreev551 [17]

0.1 mL of the stock solution of the enzyme is taken and made up to 5.0 mL with 0.001M HCl in order to prepare a 50-fold diluted enzyme.

<h3>What is dilution?</h3>

Dilution is a process of making a solution of lower concentration from a solution of higher concentration by the addition of solvent to a given volume of the solution of higher concentration.

Dilution of solutions is done using the dilution formula in order to determine the given volume of diluent or stock solution required. The dilution formula is given below:

  • C1V1 = C2V2

where:

  • C1 = Initial concentration of enzyme
  • C2 = Final concentration of enzyme
  • V1 = Initial volume
  • V2 = Final volume

For the enzyme dilution;

C1 = 1 mg/mL

C2 = 1/50 mg/ml = 0.02 mg/ml

V= ?

V2 = 5 ml

V1 = C2V2/C1

V1 =  0.02 * 5/1 = 0.1 mL

Therefore, 0.1 mL of the stock solution of the enzyme is taken and made up to 5.0 mL with 0.001M HCl in order to prepare a 50-fold diluted enzyme.

Learn more about dilution at: brainly.com/question/24881505

#SPJ1

3 0
2 years ago
To separate hard candie and marbles what is the efficient method
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3 0
4 years ago
Calculate the volume in milliliters of a 2.09 M silver nitrate solution that contains 400 g of silver nitrate AgNO3. Round your
Liula [17]

<u>Answer:</u> The volume of solution is 1.13 L

<u>Explanation:</u>

To calculate the volume of solution, we use the equation used to calculate the molarity of solution:

\text{Molarity of the solution}=\frac{\text{Mass of solute}}{\text{Molar mass of solute}\times \text{Volume of solution (in L)}}

We are given:

Molarity of solution = 2.09 M

Given mass of silver nitrate = 400. g

Molar mass of silver nitrate = 170 g/mol

Putting values in above equation, we get:

2.09M=\frac{400}{170\times \text{Volume of solution}}\\\\\text{Volume of solution}=\frac{400}{170\times 2.09}=1.13L

Hence, the volume of solution is 1.13 L

4 0
3 years ago
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