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marta [7]
3 years ago
10

Please help me with these questions

Chemistry
1 answer:
zaharov [31]3 years ago
5 0
I’m just answering this so i can ask more questions and it has to be 20 words long so i hope you figure your problems out and merry christmas happy new year
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The ksp of pbi2 is 1.4 x 10-8. what is the molar solubility of lead(ii iodide in a solution of 0.400 m sodium iodide?
tino4ka555 [31]
The solubility product of a substance us calculated by the product of the concentration of the dissociated ions in the solution raise to the stoichiometric coefficient of the ions. Therefore, we need the dissociation reaction. For this, it will have the reaction:

PbI2 = Pb^2+ + 2I-

We solve as follows:

Ksp = [Pb2+][I-]^2 = <span>1.4 x 10-8
</span><span>1.4 x 10-8 = x(2x)^2
</span><span>1.4 x 10-8 = 4x^3
x = 1.5x10^-3 M

The molar solubility would be </span>1.5x10^-3 M.
8 0
3 years ago
calculate the quantity of 0.001 m aq naoh needed to neutralize the hcl produced by complete solvolysis
abruzzese [7]

The quantity of 0.001 m aq naoh needed to neutralize the hcl produced by complete solvolysis is 200 ml.

Solvolysis is a type of nucleophilic substitution or elimination wherein the nucleophile is a solvent molecule. function of SN1 reactions, solvolysis of a chiral reactant provides the racemate.

Calculation :-

using the titration equation,

M₁V₁ = M₂V₂

substituting values

V₁ = M₂ V₂/M₁

  = 0.2 × 10 ml /0.01

= 2/0.01 ml

= 200 ml.

A reaction in which the solvent is a reactant, and turns into part of the response product. Hydrolysis of tert-butyl chloride; solvent = water. Fischer esterification reaction; solvent = methanol. related phrases: Alcoholysis, aminolysis.

Learn more about solvolysis here:-brainly.com/question/29555642

#SPJ4

<u />

<u>Disclaimer:- your question is incomplete, please see below for the complete question.</u>

Calculate the quantity of 0.01M aq NaOH needed to neutralize the HCl produced by complete solvolysis of the t-BuCl in 10ml of 0.2M t-BuCl in acetone.

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What group of elements generally have the lowest second ionization energy?
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