Please help me with these questions

Chemistry

1 answer:

zaharov [31]2 years ago

5 0

I’m just answering this so i can ask more questions and it has to be 20 words long so i hope you figure your problems out and merry christmas happy new year

You might be interested in

7. If the pOH of an RbOH solution is 6.32, what is the concentration (molarity) of the base?

liubo4ka [24]

4.79 x 10⁻⁷moldm⁻³

Explanation:

Given parameters:

pOH of RbOH = 6.32

Unknown:

Molarity of the base = ?

Solution:

The pH or pOH scale is used for expressing the level of acidity alkalinity of aqueous solutions.

pOH = -log[OH⁻]

we know the pOH to be 6.32

6.32 = -log[OH⁻]

[OH⁻] = inverse log₁₀(6.32)

[OH⁻] = 4.79 x 10⁻⁷moldm⁻³

Learn more:

pH brainly.com/question/12985875

#learnwithBrainly

6 0

3 years ago

What is the charge of a magnesium ion?

kupik [55]

2+ charge electrons of course

7 0

3 years ago

Read 2 more answers

Vanillin (used to flavor vanilla ice cream and other foods) is the substance whose aroma the human nose detects in the smallest

balu736 [363]

Answer:

Cost to supply enough vanillin is $3.2\$$

Explanation:

Threshold limit of vanillin in air is $2.0\times 10^{-11}g$ per litre means there should be $2.0\times 10^{-11}g$ of vanillin in 1L of air to detect aroma of vanillin.

$1ft^{3}=28.32L$

So, $5.0\times 10^{7}ft^{3}=(5.0\times 10^{7}\times 28.32)L$

So amount of vanillin should be present to detect = $(2.0\times 10^{-11}\times 5.0\times 10^{7}\times 28.32)g$

As cost of 50 g vanillin is $112\$$ therefore cost of $(2.0\times 10^{-11}\times 5.0\times 10^{7}\times 28.32)g$ vanillin = $(2.0\times 10^{-11}\times 5.0\times 10^{7}\times 28.32\times 112)\$ = 3.2\$$