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3 years ago

Why does water boils at a higher temperature than a non-polar solvent like ether?

Chemistry

1 answer:

trapecia [35]3 years ago

8 0

a large amount of energy is released when water dissociates into oppositely charged ions.

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2.2 Chromium has four naturally-occurring isotopes: 4.34% of 50Cr, with an atomic weight of 49.9460 amu; 83.79% of 52Cr, with an

shutvik [7]

Answer:

Average atomic mass = 51.9963 amu

Explanation:

Given data:

Abundance of Cr⁵⁰ with atomic mass= 4.34% , 49.9460 amu

Abundance of Cr⁵² with atomic mass = 83.79%, 51.9405 amu

Abundance of Cr⁵³ with atomic mass =9.50%, 52.9407 amu

Abundance of Cr⁵⁴ with atomic mass = 2.37%, 53.9389 amu

Average atomic mass = 51.9963 amu

Solution:

Average atomic mass = (abundance of 1st isotope × its atomic mass) +(abundance of 2nd isotope × its atomic mass +....n) / 100

Average atomic mass = (4.34×49.9460)+(83.79×51.9405) +(9.50×52.9407)+ (2.37×53.9389) / 100

Average atomic mass = 216.7656 + 4352.0945 + 502.9367 +127.8352 / 100

Average atomic mass = 5199.632 / 100

Average atomic mass = 51.9963 amu

4 0

3 years ago

Which projectiles will be visibly affected by air resistance when they fall?

Anika [276]

All of the above will be affected by air resistance, but the most obvious will be the balloon or leaf.
Hope it helps somewhat!

8 0

4 years ago

Read 2 more answers

Help meh......please...

Mrrafil [7]

Answer:

The third one

Explanation:

Nickel-62 has the highest binding energy per nucleon of any isotope for any element. Isotopes heavier than 62Ni cannot be formed by nuclear fusion without losing energy.

3 0

3 years ago

If 62.3 mL of lead(II) nitrate solution reacts completely with excess sodium iodide solution to yield 0.862 g of precipitate, wh

Alexxx [7]

Answer:

The molarity of the lead(II) ion in the original solution is 0.03M

Explanation:

Step 1: The balanced reaction

Pb(NO3)2(aq) + 2 NaI aq) → PbI2(s) + 2 NaNO3 (aq)

Pb2+ + 2I- →PbI2

This means that for 1 mole Pb2+ consumed, there is needed 2 moles of I- to produce 1 mole of PbI2

Step 2: Calculate moles of PbI2

Moles of PbI2 = 0.862g / 461.01 g/mole

moles of PbI2 = 0.00187 moles

Step 3: calculate moles of Pb2+

For 1 mole of PbI2 produced we need 1 mole of Pb2+

This means for 0.00187 moles of PbI2 we need 0.00187 moles of Pb2+

Step 4: Calculate the molarity of the Pb2+ ion

Molarity of Pb2+ = moles of Pb2+ / volume =

Molarity of Pb2+ = 0.00187 moles / 62.3*10^-3

Molarity of Pb2+ ion = 0.03M

The molarity of the lead(II) ion in the original solution is 0.03M

5 0

3 years ago

Can anyone please answer questions 3 and 4 I’ll give the brainiest!

mel-nik [20]

Answer:

1.Phenolphthalein

2.Method

a.Use the pipette and pipette filler to add 25 cm 3 of alkali to a clean conical flask.

b.Add a few drops of indicator and put the conical flask on a white tile.

c.Fill the burette with acid and note the starting volume.

d.Slowly add the acid from the burette to the alkali in the conical flask, swirling to mix.

Explanation:

4 0

2 years ago