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GalinKa [24]
3 years ago
10

If 40.0 g of HCl react with an excess of magnesium metal, what is the theoretical yield of hydrogen?

Chemistry
2 answers:
Bezzdna [24]3 years ago
6 0

Answer is A, 1.11 g .

mamaluj [8]3 years ago
5 0
Balanced equation: Mg+2HCl=MgCl2 + H2
Showing that if Mg is not a limiting factor then 2 moles of HCl on complete reaction liberate 1 mole of Hydrogen
therefore:
1 mole of HCl=35.5g, 40g=x
X= 40/35.5= 1.127mole
2 moles of HCl = 1 moles of Hydrogen
1.127=X
X=1.127/2 = 0.56
the theoretical yield of hydrogen
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Answer:

We will need 147.772 mL of KH2PO4 to make this solution

Explanation:

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H2PO4 - ⇄ H+ + HPO42-

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7.05 = 7.21 + log [HPO42-]/[H2PO4-]

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0.6918 = [HPO42-]/[H2PO4-]

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Since both have a concentration of 1M = 1 mol /L

If we plug this in the equation 0.6918 = [HPO42-]/[H2PO4-]

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172.95 = 1.6918x

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To control this we can plug this in the pH equation

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