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Norma-Jean [14]

3 years ago

6

Calculate the area of the shaded region

2 answers:

Soloha48 [4]3 years ago

5 0

Answer:

24π ≈ 75.36

Step-by-step explanation:

First find the area of the circle given the radius

πr² = π (8²) = 64π

The shaded region of the circle to the entire area of the circle is 3/8

Therefore multiply 64π by 3/8 to get your answer

This gives you 24π

Blababa [14]3 years ago

5 0

Answer:

75.36

Step-by-step explanation:

the first step is to find the area of the circle

area is pi x radius^2

3.14 times 64 is ~ 200.96

the next step is to set up a porportion.

135/360 =x/200.96

cross multiply

135 times 200.96 =27129.6

the divide that by 360

x is 75.36

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Write a two-column proof on a space provided

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Explain why the sum of the angle measures in any triangle is 180

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3 years ago

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<img src="https://tex.z-dn.net/?f=%20%5Cfrac%7Bx%20%2B%201%20%7D%7B2%7D%20%20%3D%20%20%5Cfrac%7B7x%20-%203%7D%7B2%7D%20" id="Tex

MAVERICK [17]

Answer:

$\sf x =\dfrac{2}{3}$

Explanation:

$\sf \rightarrow \dfrac{x+1}{2} = \dfrac{7x-3}{2}$

cross multiply

$\sf \rightarrow 2(x+1) = 2(7x-3)$

divide both sides by 2

$\sf \rightarrow x + 1 = 7x-3$

isolate variables

$\sf \rightarrow x -7x = -3-1$

simplify

$\sf \rightarrow -6x = -4$

divide both sides by -6

$\sf \rightarrow \dfrac{-6x}{-6} = \dfrac{-4}{-6}$

simplify

$\sf \rightarrow x =\dfrac{2}{3}$

4 0

2 years ago

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Evaluate 23x-1 for x = 1.

swat32

22 is the answer for 23x-1 for x=1

8 0

4 years ago

Help appreciated on question in image!<br> Thanks:)

Verdich [7]

Answer:

$x=-1,\:x=-7,\:x=i,\:x=-i$

Step-by-step explanation:

Considering the equation

$x^4+8x^3+8x^2+8x+7=0$

Solving

$x^4+8x^3+8x^2+8x+7$

$\mathrm{Factor\:}x^4+8x^3+8x^2+8x+7:\quad \left(x+1\right)\left(x+7\right)\left(x^2+1\right)$

As

$\mathrm{Use\:the\:rational\:root\:theorem}$

$a_0=7,\:\quad a_n=1$

$\mathrm{The\:dividers\:of\:}a_0:\quad 1,\:7,\:\quad \mathrm{The\:dividers\:of\:}a_n:\quad 1$

$\mathrm{Therefore,\:check\:the\:following\:rational\:numbers:\quad }\pm \frac{1,\:7}{1}$

$-\frac{1}{1}\mathrm{\:is\:a\:root\:of\:the\:expression,\:so\:factor\:out\:}x+1$

$=\left(x+1\right)\frac{x^4+8x^3+8x^2+8x+7}{x+1}...[A]$

Solving

$\frac{x^4+8x^3+8x^2+8x+7}{x+1}$

$=x^3+7x^2+x+7$

Putting $\frac{x^4+8x^3+8x^2+8x+7}{x+1}$ = $x^3+7x^2+x+7$ in equation [A]

So,

$\left(x+1\right)\frac{x^4+8x^3+8x^2+8x+7}{x+1}...[A]$

$=\left(x+1\right)x^3+7x^2+x+7$

As

$x^3+7x^2+x+7=\left(x+7\right)\left(x^2+1\right)$

So,

Equation [A] becomes

$=\left(x+1\right)\left(x+7\right)\left(x^2+1\right)$

So, the polynomial equation becomes

$\left(x+1\right)\left(x+7\right)\left(x^2+1\right)=0$

$\mathrm{Using\:the\:Zero\:Factor\:Principle:\quad \:If}\:ab=0\:\mathrm{then}\:a=0\:\mathrm{or}\:b=0\:\left(\mathrm{or\:both}\:a=0\:\mathrm{and}\:b=0\right)$ $\mathrm{Solve\:}\:x+1=0:\quad x=-1$

$\mathrm{Solve\:}\:x+7=0:\quad x=-7$

$\mathrm{Solve\:}\:x^2+1=0:\quad x=i,\:x=-i$

$\mathrm{The\:solutions\:are}$

$x=-1,\:x=-7,\:x=i,\:x=-i$

Keywords: polynomial equation

Learn polynomial equation from brainly.com/question/12240569

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3 years ago

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