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3 years ago

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A 350 −Ω resistor and a 6.40 −μF capacitor are connected in parallel to an ac generator that supplies an rms voltage of 220 V at

an angular frequency of 360 rad/s . Note that since there is no inductor in the circuit, the 1/ωL term is not present in the expression for Z. Find the current amplitude in the resistor..

1 answer:

sergiy2304 [10]3 years ago

6 0

Answer:

The current amplitude in the resistor is 0.889 A.

Explanation:

Given that,

Resistor $R= 350\ \Omega$

Capacitor $C=6.40\ \mu F$

Voltage $V_{rms} = 220 V$

Frequency = 360 rad/s

We need to calculate the current amplitude in the resistor

Using formula of current amplitude

$I_{max}=\dfrac{V_{max}}{R}$

$I_{max}=\dfrac{V_{rms}\sqrt{2}}{R}$

Put the value into the formula

$I_{max}=\dfrac{220\sqrt{2}}{350}$

$I_{max}=0.889\ A$

Hence, The current amplitude in the resistor is 0.889 A.

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