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patriot [66]
3 years ago
13

A 350 −Ω resistor and a 6.40 −μF capacitor are connected in parallel to an ac generator that supplies an rms voltage of 220 V at

an angular frequency of 360 rad/s . Note that since there is no inductor in the circuit, the 1/ωL term is not present in the expression for Z. Find the current amplitude in the resistor..
Physics
1 answer:
sergiy2304 [10]3 years ago
6 0

Answer:

The current amplitude in the resistor is 0.889 A.

Explanation:

Given that,

Resistor R= 350\ \Omega

Capacitor C=6.40\ \mu F

Voltage V_{rms} = 220 V

Frequency = 360 rad/s

We need to calculate the current amplitude in the resistor

Using formula of current amplitude

I_{max}=\dfrac{V_{max}}{R}

I_{max}=\dfrac{V_{rms}\sqrt{2}}{R}

Put the value into the formula

I_{max}=\dfrac{220\sqrt{2}}{350}

I_{max}=0.889\ A

Hence, The current amplitude in the resistor is 0.889 A.

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A rigid tank contains 1 kg of air (ideal gas) at 15 °C and 210 kPa. A paddle wheel supplies work input to the air such that fina
lisov135 [29]

Answer:

-58.876 kJ

Explanation:

m = mass of air = 1 kg

T₁ = Initial temperature = 15°C

T₂ = Final temperature = 97°C

Cp = Specific heat at constant pressure = 1.005 kJ/kgk

Cv = Specific heat at constant volume = 0.718 kJ/kgk

W = Work done

Q = Heat = 0 (since it is not mentioned we are considering adiabatic condition)

ΔU = Change in internal energy

Q = W+ΔU

⇒Q = W+mCvΔT

⇒0 = W+mCvΔT

⇒W = -mCvΔT

⇒Q = -1×0.718×(97-15)

⇒Q = -58.716 kJ

5 0
3 years ago
3. A large crane lifts a 25,000 kg mass in the air. The amount of work that must be done by the
andreev551 [17]

\mathfrak{\huge{\orange{\underline{\underline{AnSwEr:-}}}}}

Actually Welcome to the concept of Efficiency.

Here we can see that, the Input work is given as 2.2 x 10^7 J and the efficiency is given as 22%

The efficiency is => 22% => 22/100.

so we get as,

E = W(output) /W(input)

hence, W(output) = E x W(input)

so we get as,

W(output) = (22/100) x 2.2 x 10^7

=> W(output) = 0.22 x 2.2 x 10^7 => 0.484 x 10^7

hence, W(output) = 4.84 x 10^6 J

The useful work done on the mass is 4.84 x 10^6 J

5 0
3 years ago
Objects have a tendency to resist changing their motion. This property is called: *
Salsk061 [2.6K]

Answer:

The answer your looking for is option 2 - Inertia

3 0
3 years ago
A 2.2 kgkg block slides along a frictionless surface at 1.2 m/sm/s . A second block, sliding at a faster 4.0 m/sm/s , collides w
aleksklad [387]

Answer:

0.6kg

Explanation:

the unknown here is the mass of the second block

applying the law of the conservation of momentum

m₁v₁ + m₂v₂ = (m₁ + m₂) v₃

where m₁=mass of first block=2.2kg

m₂=mass of colliding block= ?

v₁= velocity of first block=1.2m/s

v₂=velocity of colliding block=4.0m/s

v₃= final velocity of combined block=1.8m/s

applying the formula above

(2.2 × 1.2) + (m₂ × 4) = (2.2 + m₂) × 1.8

2.64 + 4m₂ = 3.96 + 1.8m₂

collecting like terms

4m₂ - 1.8m₂ = 3.96 - 2.64

2.2m₂=1.32

divide both sides by 2.2

m₂= 0.6kg

4 0
3 years ago
Pierre cycles at 4 miles per hour and travels a distance of 13 miles. How long
amm1812

Answer:

His journey took him 3 hours 15 minutes.

Explanation: 4 miles every hour. So 1 hr is equal to 4 miles, 2 hrs is equal to 8 miles, 3 hrs is equal to 12 miles. Now he just has 1 miles left, and since it takes him a hour to cycle 4 miles, 60 divided by 4 is 15. Therefore, 1 mile is equal to 15 minutes.

4 0
3 years ago
Read 2 more answers
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