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patriot [66]
3 years ago
13

A 350 −Ω resistor and a 6.40 −μF capacitor are connected in parallel to an ac generator that supplies an rms voltage of 220 V at

an angular frequency of 360 rad/s . Note that since there is no inductor in the circuit, the 1/ωL term is not present in the expression for Z. Find the current amplitude in the resistor..
Physics
1 answer:
sergiy2304 [10]3 years ago
6 0

Answer:

The current amplitude in the resistor is 0.889 A.

Explanation:

Given that,

Resistor R= 350\ \Omega

Capacitor C=6.40\ \mu F

Voltage V_{rms} = 220 V

Frequency = 360 rad/s

We need to calculate the current amplitude in the resistor

Using formula of current amplitude

I_{max}=\dfrac{V_{max}}{R}

I_{max}=\dfrac{V_{rms}\sqrt{2}}{R}

Put the value into the formula

I_{max}=\dfrac{220\sqrt{2}}{350}

I_{max}=0.889\ A

Hence, The current amplitude in the resistor is 0.889 A.

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The 1350-kg car has a velocity of 24 km/h up the 8-percent grade when the driver applies more power for 18 s to bring the car up
Brrunno [24]

Answer:

Explanation:

We shall apply concept of impulse to solve the problem  .

Impulse = force x time

impulse = change in momentum

force x time = change in momentum

initial speed u = 24 km/h = 6.67 m /s

final speed v = 65 km/h = 18.05 m /s

change in momentum = m v - mu

= m ( v-u )

= 1350 ( 18.05 - 6.67 )

= 15363 kg m/s

F x 18 = 15363

F = 853.5 N .

4 0
3 years ago
A 72.9-kg base runner begins his slide into second base when moving at a speed of 4.02 m/s. The coefficient of friction between
elena-14-01-66 [18.8K]

Answer:

-589.05 J

Explanation:

Using work-kinetic energy theorem, the work done by friction = kinetic energy change of the base runner

So, W = ΔK

W = 1/2m(v₁² - v₀²) where m = mass of base runner = 72.9 kg, v₀ = initial speed of base runner = 4.02 m/s and v₁ = final speed of base runner = 0 m/s(since he stops as he reaches home base)

So, substituting the values of the variables into the equation, we have

W = 1/2m(v₁² - v₀²)

W = 1/2 × 72.9 kg((0 m/s)² - (4.02 m/s)²)

W = 1/2 × 72.9 kg(0 m²/s² - 16.1604 m²/s²)

W = 1/2 × 72.9 kg(-16.1604 m²/s²)

W = 1/2 × (-1178.09316 kgm²/s²)

W = -589.04658 kgm²/s²

W = -589.047 J

W ≅ -589.05 J

4 0
3 years ago
Solve for M₂
soldi70 [24.7K]

Explanation:

M₂ = Fr²/GM₁

M₂ = [(132N)(.243m)²]/[(6.67*10^-11N*m²/kg)(1.175*10^4kg)]

M₂ = (7.79N*m²)/(7.84*10^-7N*m²)

M₂ = 9.94*10^6 kg

5 0
3 years ago
Water, oil and silver are poured into the vessel
taurus [48]

The height of the oil column above the water in the vessel is determined as 2 cm.

<h3>Pressure of the vessel</h3>

The pressure of the vessel due to water, oil and silver poured into the vessel is determined from mercury column.

let level of mercury = 20 cm + 0.5 cm = 20.5 cm

20.5 cmHg = 205 mmHg

1 mmHg = 133.32 Pa

205 mmHg = 27,330.6 Pa

<h3>Height of the liquids in the vessel</h3>

P = ρgh

where;

ρ is the density of water, oil and silver respectively

ρ = 1000 kg/m³ + 881 kg/m³ + 10,800 kg/m³ = 12,681 kg/m³

h = P/(ρg)

h = (27,330.6) / (12,681 x 9.8)

h = 0.22 m

h = 22 cm

<h3>Height of oil column</h3>

Oil is less dense than water and will float on water.

Height of oil column = 22 cm - 20 cm = 2 cm

Learn more about density here: brainly.com/question/6838128

#SPJ1

7 0
2 years ago
Which item is necessary to make an electromagnet? Question 4 options: Render of a wooden cube with sharp edges, coordinating pat
BlackZzzverrR [31]

The electromagnet is a device that requires conducting wires wrapped around the iron core.

For making an electromagnet, the most necessary item is a copper wire.

What is an Electromagnet?

An electromagnet is a device that has conducting wires wrapped around an iron core. When electricity is passed through the wires, a magnetic field is generated. The setup acts as a strong magnet.

In order to make an electromagnet, a current-carrying wire is needed to wrap around a magnetic material. The current-carrying wires will play the role of conducting wires and the conducting wires are necessary to make an electromagnet. These wires can be made of copper.

Thus, we can conclude that for making an electromagnet, the most necessary item is a copper wire.

Learn more about the electromagnet here:

brainly.com/question/10060657

4 0
2 years ago
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