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patriot [66]
3 years ago
13

A 350 −Ω resistor and a 6.40 −μF capacitor are connected in parallel to an ac generator that supplies an rms voltage of 220 V at

an angular frequency of 360 rad/s . Note that since there is no inductor in the circuit, the 1/ωL term is not present in the expression for Z. Find the current amplitude in the resistor..
Physics
1 answer:
sergiy2304 [10]3 years ago
6 0

Answer:

The current amplitude in the resistor is 0.889 A.

Explanation:

Given that,

Resistor R= 350\ \Omega

Capacitor C=6.40\ \mu F

Voltage V_{rms} = 220 V

Frequency = 360 rad/s

We need to calculate the current amplitude in the resistor

Using formula of current amplitude

I_{max}=\dfrac{V_{max}}{R}

I_{max}=\dfrac{V_{rms}\sqrt{2}}{R}

Put the value into the formula

I_{max}=\dfrac{220\sqrt{2}}{350}

I_{max}=0.889\ A

Hence, The current amplitude in the resistor is 0.889 A.

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m_{1}*v_{1x}+m_{2}*v_{2x}=m_{1}*v_{fx1}+m_{2}*v_{fx2}\\m*(v_{1x}+v_{2x})=m*(v_{fx1}+v_{fx2})\\v_{fx2}=0\\v_{1x}+v_{2}=v_{f1}+0\\v_{fx1}=2.2 \frac{m}{s}+(1.2\frac{m}{s})\\  v_{fx1}=1 \frac{m}{s} \\

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