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patriot [66]
3 years ago
13

A 350 −Ω resistor and a 6.40 −μF capacitor are connected in parallel to an ac generator that supplies an rms voltage of 220 V at

an angular frequency of 360 rad/s . Note that since there is no inductor in the circuit, the 1/ωL term is not present in the expression for Z. Find the current amplitude in the resistor..
Physics
1 answer:
sergiy2304 [10]3 years ago
6 0

Answer:

The current amplitude in the resistor is 0.889 A.

Explanation:

Given that,

Resistor R= 350\ \Omega

Capacitor C=6.40\ \mu F

Voltage V_{rms} = 220 V

Frequency = 360 rad/s

We need to calculate the current amplitude in the resistor

Using formula of current amplitude

I_{max}=\dfrac{V_{max}}{R}

I_{max}=\dfrac{V_{rms}\sqrt{2}}{R}

Put the value into the formula

I_{max}=\dfrac{220\sqrt{2}}{350}

I_{max}=0.889\ A

Hence, The current amplitude in the resistor is 0.889 A.

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Estimate the water volume in the graduated cylinder to the nearest 0.1 mL.
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Answer:

With a 50-mL graduated cylinder, read and record the volume to the nearest 0.1 mL. The 10-mL graduated cylinder scale is read to the nearest 0.01 mL and the 500-mL graduated cylinder scale is read to the nearest milliliter (1 mL). A buret is a scaled cylindrical tube attached to a stopcock, or valve.

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3 years ago
A thin spherical shell with radius R1 = 4.00 cm is concentric with a larger thin spherical shell with radius R2 = 6.00 cm . Both
kakasveta [241]

Answer:

The right response will be "450 volts".

Explanation:

The given values are:

R1 = 4.00 cm

R2 = 6.00 cm

q1 = +6.00 nC

q2 = −9.00 nC

As we know,

The potential difference between the two shell's difference will be:

⇒  \Delta V=K[(\frac{q1}{R1}+\frac{q2}{R2})-(\frac{q1}{R1} +(\frac{q2}{R2}))]

           =K[\frac{q1}{R2}-\frac{q1}{R1} ]

On substituting the values, we get

           =(9\times 10^9)[\frac{6\times 10^{-9}}{0.04}-\frac{6\times 10^{-9}}{0.06}]  

       Δ =450 \ volts

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3 years ago
Rube goldberg machine steps
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Answer:

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2 years ago
An advertisement for an all-terrain vehicle (ATV) claims that the ATV can climb inclined slopes of 35°. What is the minimum coef
navik [9.2K]

An advertisement for an all-terrain vehicle (ATV) claims that the ATV can climb inclined slopes of 35°. The minimum coefficient of static friction needed for this claim to be possible is 0.7

In an inclined plane, the coefficient of static friction is the angle at which an object slide over another.  

As the angle rises, the gravitational force component surpasses the static friction force, as such, the object begins to slide.

Using the Newton second law;

\sum F_x = \sum F_y = 0

\mathbf{mg sin \theta -f_s= N-mgcos \theta = 0 }

  • So; On the L.H.S

\mathbf{mg sin \theta =f_s}

\mathbf{mg sin \theta =\mu_s N}

  • On the R.H.S

N = mg cos θ

Equating both force component together, we have:

\mathbf{mg sin \theta =\mu_s \ mg \ cos \theta}

\mathbf{sin \theta =\mu_s \ \ cos \theta}

\mathbf{\mu_s = \dfrac{sin \theta }{ cos \theta}}

From trigonometry rule:

\mathbf{tan \theta= \dfrac{sin \theta }{ cos \theta}}

∴

\mathbf{\mu_s =\tan \theta}}

\mathbf{\mu_s =\tan 35^0}}

\mathbf{\mu_s = 0.700}}

Therefore, we can conclude that the minimum coefficient of static friction needed for this claim to be possible is 0.7

Learn more about static friction here:

brainly.com/question/24882156?referrer=searchResults

8 0
2 years ago
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