Explanation:
The range <em>R</em> of a projectile is given the equation
The maximum range is achieved when 
so our equation reduces to
We can solve for the initial velocity 
as follows:
or
To find the maximum altitude H reached by the missile, we can use the equation
At its maximum height H, 
so we can write
or
![\:\:\:\:\:\:= \dfrac{[(9.6×10^3\:\text{m/s})\sin{45°}]^2}{2(9.8\:\text{m/s}^2)}](https://tex.z-dn.net/?f=%5C%3A%5C%3A%5C%3A%5C%3A%5C%3A%5C%3A%3D%20%5Cdfrac%7B%5B%289.6%C3%9710%5E3%5C%3A%5Ctext%7Bm%2Fs%7D%29%5Csin%7B45%C2%B0%7D%5D%5E2%7D%7B2%289.8%5C%3A%5Ctext%7Bm%2Fs%7D%5E2%29%7D)
Answer:
53 minutes
Explanation:
To solve this problem, we need to use common proportions to convert.
= 11.7km * 1mi/1.61km * 1hr/8.2mi * 60min/hr
≈ 53 minutes
Best of LUck!
This is the Doppler effect.
1. As the sound leaves the horn the sound waves are at first close to each other and as they move outwards they become further apart. The closer the sound waves are the louder the noise.
As the car gets the closer the sound waves get closer, so the horn becomes louder.
2. As the horn moves away, the sound waves become less frequent, causing the pitch to get lower.
Answer:
3.066×10^21 photons/(s.m^2)
Explanation:
The power per area is:
Power/A = (# of photons /t /A)×(energy / photon)
E/photons = h×c/(λ)
photons /t /A = (Power/A)×λ /(h×c)
photons /t /A = (P/A)×λ/(hc)
photons /t /A = (680)×(678×10^-9)/(6.63×10^-34)×(3×10^-8)
= 3.066×10^21
Therefore, the number of photons per second per square meter 3.066×10^21 photons/(s.m^2).
