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3 years ago

Gravity is a force that pulls an object down towards the Earth. Can we see the force of gravity?

Physics

2 answers:

Alexeev081 [22]3 years ago

6 0

Answer:

We can't actually see the force of gravity BUT we can see its effect.

nikitadnepr [17]3 years ago

4 0

Answer:

hope my answer helps you mark me brianliest （⌒▽⌒）

Explanation:

Even you exert a gravitational force on other objects. Because your mass is so much less than the mass of the Earth, you can't feel your gravitational force. ... Because the Earth's gravity has the same pull on every object, all objects fall at the same speed (in a vacuum),and alsoGravity not only pulls on mass but also on light. Albert Einstein discovered this principle. If you shine a flashlight upwards, the light will grow imperceptibly redder as gravity pulls it. You can't see the change with your eyes, but scientists can measure it.

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Sometimes earthquakes occur at a boundary between the Indian and Eurasian Plates. The collisions of these two

gavmur [86]

Answer:

A) Continental - Continental convergent

Explanation:

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3 years ago

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Which factor most directly affects the flow of ocean currents?

nordsb [41]

The factor that most affects the flow of ocean currents is B. differences in temperature.

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4 years ago

The figure shows the speed of a person's body as he does a chin-up. Assume the motion is vertical and the mass of the person's b

pochemuha

Please check calculations and let me know later on

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4 years ago

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An electron moves in a circular path perpendicular to a magnetic field of magnitude 0.220 T. If the kinetic energy of the electr

Gwar [14]

Answer:

$971605.66\ \text{m/s}$

$25.1\ \mu\text{m}$

Explanation:

m = Mass of electron = $9.11\times 10^{-31}\ \text{kg}$

B = Magnetic field = 0.22 T

K = Kinetic energy of electron = $4.3\times 10^{-19}\ \text{J}$

q = Charge = $1.6\times 10^{-19}\ \text{C}$

v = Velocity of electron

r = Radius of curved path

Kinetic energy is given by

$K=\dfrac{1}{2}mv^2\\\Rightarrow v=\sqrt{\dfrac{2K}{m}}\\\Rightarrow v=\sqrt{\dfrac{2\times 4.3\times 10^{-19}}{9.11\times 10^{-31}}}\\\Rightarrow v=971605.66\ \text{m/s}$

The speed of the electron is $971605.66\ \text{m/s}$

The force balance of the system is given by

$qvB=\dfrac{mv^2}{r}\\\Rightarrow r=\dfrac{mv}{qB}\\\Rightarrow r=\dfrac{9.11\times 10^{-31}\times 971605.66}{1.6\times 10^{-19}\times 0.22}\\\Rightarrow r=0.0000251=25.1\ \mu\text{m}$

The radius of the curved path is $25.1\ \mu\text{m}$

6 0

3 years ago

A spring is compressed between two cars on a frictionless airtrack. Car A has four times the mass of car B, MA = 4 MB, while the

Free_Kalibri [48]

Answer:

10. True. vA = - ¼ vB , pA = - pB

Explanation:

Let us propose the solution of this problem, as the cars are released let us use the conservation of the moment.

Initial before releasing the cars

p₀ = 0

Final after releasing cars

$p_{f}$ = mA vA + mB vB

p₀ = $p_{f}$

0 = mA vA + mB vB

vA = - mB / mA vB

They indicate that mA = 4 mB

vA = - ¼ vB

Let's write the amount of movement for each body

pA = mA vA = 4 mB (- ¼ vB

pA = -mB vB

pB = mB vB

pA = - pB

Let's check the answers

1 False

2 False

3 False

4 false

5 False

6 False

7 False

8 False

9 False

10. True. The speed and amount of movement values are correct

6 0

4 years ago