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N76 [4]
3 years ago
11

In recent research, strontium ions have been used for bone regeneration within humans as a calcium replacement. Based on your kn

owledge of periodic information, explain why is strontium a good substitute for calcium instead of other elements on the periodic table. [Hint: think about the way elements are organized based on their common characteristics] *
Chemistry
1 answer:
Gnom [1K]3 years ago
5 0

Answer:

Strontium, as opposed to other elements on the periodic table (with the exception of others in the same group/column i.e., the vertical direction), is a good substitute for Calcium because they are in the same group.

Explanation:

This is because elements of the same group behave similarly and have similar properties. This is due to the fact that elements of the same group (in the vertical direction) have the same number of valence electrons.

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I really do not know how to do this, I already asked my teacher to explain it to me, but I still don’t understand. Can someone p
Gala2k [10]

1. to calculate molar mass , you need average atomic mass of each element.

formula is simple

suppose we have Na2CO3

here it says

there are

2 atoms of Na

1 atom of C

3 atom of O

now

molar mass = (total atoms of Na × average atomic mass of Na) + ( total atom of C × average atomic mass of C )+ (total atom of O × average atomic mass of O)

i hope you can figure out it now.

in case of (NH4)2

this means you have 2 count of NH4

so total atoms of N = 2

total atoms of H = 4×2 = 8

so on you can now figure it out

2. balanced equation

here LHS and RHS shoild have same number of atoms of each element .

for example

H2 + Cl2 => 2HCl

here 2 atoms of H combined with 2 atoms of Cl , we know H and Cl combined and formed HCl now because total H atoms are 2 and Cl atoms are 2 in LHS then we should also have 2 atoms of each in right side

so thats why we have 2HCl in right side.

Try to figure out . let me know if need any help

3 0
3 years ago
How many moles of malachite should be formed when 1.5 moles of copper sulphate reacts with an excess of sodium carbonate?
Katen [24]
2 Na₂CO₃ + 2 CuSO₄ + H₂O → CuCO₃.Cu(OH)₂ + 2 Na₂SO₄ + CO₂
Malachite molar mass = 221.1 g / mol
So 2 moles CuSO₄ produce 1 mole of malachite
so 1.5 mole CuSO₄ produce (0.75) mole malachite
Mass of malachite = 0.75 mole * 221.1 g/ mol = 165.83 g 
5 0
3 years ago
he decomposition of acetaldehyde, CH3CHO, was determined to be a second order reaction with a rate constant of 0.0771 M-1 s-1. I
nataly862011 [7]

Answer:

The concentration is [-1 + sqrt(1+0.11t)]/0.1542 M

Explanation:

Let the concentration of CH3CHO after selected reaction times be y

Rate = Ky^2 = change in concentration of CH3CHO/time

K = 0.0771 M^-1 s^-1

Change in concentration of CH3CHO = 0.358 - y

0.0771y^2 = 0.358-y/t

0.0771ty^2 = 0.358 - y

0.0771ty^2 + y - 0.358 = 0

The value of y must be positive and is obtained in terms of t using the quadratic formula

y = [-1 + sqrt(1^2 -4(0.0771t)(-0.358)]/2(0.0771) = [-1 + sqrt(1+0.11t)]/0.1542 M

6 0
3 years ago
NaCl has a Delta. Hfus = 30. 2 kJ/mol. What is the mass of a sample of NaCl that needs 732. 6 kJ of heat to melt completely? Use
tia_tia [17]

The mass of NaCl sample has been 24.3 g. Thus, option A is correct.

The heat of fusion has been the amount of heat required to convert  1 mole of substance into solid to liquid state.

The heat required has been given as:

Q=m\Delta H

<h3>Computation for the mass of NaCl</h3>

The given solution has heat of fusion, \Delta H_{fus}=30.2\rm kJ/mol

The heat required to melt the sample has been, Q=732.6\;\rm kJ/mol

Substituting the values for the mass of NaCl

\rm 732.6\;kJ/mol=Mass\;\times\;30.2\;kJ/mol\\\\&#10;Mass=\dfrac{732.6}{30.2}\;g\\\\&#10; Mass=24.3\;g\\

The mass of NaCl sample has been 24.3 g. Thus, option A is correct.

Learn more about heat of fusion, here:

brainly.com/question/87248

5 0
3 years ago
2. Given the unbalanced equation:
zheka24 [161]
2 Na + 2 H2O → 2 NaOH + H2 (balanced equation)
The answer would be 2, since 2 in the coefficient of both Na and NaOH
7 0
3 years ago
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