All categories

2 years ago

The volume of a sample of gas, initially at 25 °C and 158 mL, increases to

Chemistry

1 answer:

Artist 52 [7]2 years ago

5 0

Answer:

The final temperature = 848.7 K or 575.7 °C

Explanation:

Step 1: Data given

Temperature = 25.0 °C = 298 K

Volume = 158 mL = 0.158 L

The volume increases to 450 mL = 0.450 L

The pressure is constant

Step 2: Calculate the final temperature

V1/T1 = V2/T2

⇒with V1 = the initial volume = 0.158 L

⇒with T1 = the initial temperature = 298 K

⇒with V2 = the increased volume = 0.450 L

⇒with T2 = the new temperature = TO BE DETERMINED

0.158 L / 298 K = 0.450 L / T2

T2 = 0.450 L / (0.158L/298K)

T2 = 848.7 T

The final temperature = 848.7 K or 575.7 °C

You might be interested in

How many milliliters of 0.0050 N KOH are required to neutralize 41 mL of 0.0050 M H2SO4?

Kipish [7]

Answer:

V KOH = 41 mL

Explanation:

for neutralization:

( V×C )acid = ( V×C )base

∴ C H2SO4 = 0.0050 M = 0.0050 mol/L

∴ V H2SO4 = 41 mL = 0.041 L

∴ C KOH = 0.0050 N = 0.0050 eq-g/L

∴ E KOH = 1 eq-g/mol

⇒ C KOH = (0.0050 eq-g/L)×(mol KOH/1 eq-g) = 0.0050 mol/L

⇒ V KOH = ( V×C ) acid / C KOH

⇒ V KOH = (0.041 L)(0.0050 mol/L) / (0.0050 mol/L)

⇒ V KOH = 0.041 L

4 0

2 years ago

Many double-displacement reactions are enzyme-catalyzed via the "ping pong" mechanism, so called because the reactants appear to

zhenek [66]

Answer:

D. It will decrease by a factor of 4

Explanation:

According to the question , the equation follows :

$A+B\rightarrow C+D$

Rate law : This states the rate of reaction is directly proportional to concentration of reactants with each reactant raised to some power which may or may not be equal to the stoichiometeric coefficient.

$Rate\ \alpha [A]^{a}[B]^{b}$

$r=[A]^{a}[B]^{b}$ .................(1)

STEP": First, find out the power "a" and "b"

a+b = 3 (because it is given that the reaction follow 3rd order-kinetics)

According to question, doubling the concentration of the first reactant causes the rate to increase by a factor of 2 means,

r' = 2r if [A'] = 2[A]

Here [B] is uneffected means [B']=[B]

hence new rate =

$r'=[A']^{a}[B']^{b}$

Put the value of [A'] , [B'] and r' in the above equation:

$2r=[2A]^{a}[B]^{b}$ ...........(2)

Divide equation (1) by (2) we , get

$\frac{2r}{r}=\frac{[2A]^{2}[B]^{b}}{[A]^{a}[B]^{b}}$

$2= 2(\frac{A}{A})^{a}\times (\frac{B}{B})^{b}$

Here A and A cancel each other

B and B cancel each other

We get,

$2= 2^{a}\times 1^{b}$

1^b = 1 ( power of 1 = 1)

$2= 2^{a}$

This is possible only when a = 1

We know that : a + b = 3

1 + b = 3

b =3 -1 = 2

b = 2

Hence the rate law becomes :

$r=[A]^{a}[B]^{b}$

$r=[A]^{1}[B]^{2}$ .............(3)

Look in the question now, it is asked to calculate the concentration of [B],if cut in half

Hence

[B']=1/2[B]

Insert the value of [B'] in equation (3)

$r'=[A]^{1}[B']^{2}$

$r'=[A]^{1}(\frac{1}{2}[B])^{2}$

$r'=\frac{1}{4}[A]^{1}[B]^{2}$ ............(a)

But

$r=[A]^{a}[B]^{b}$ ..............(b)

Compare equation (a) and (b) , we get

new rate r' =

r' = 1/4 r

7 0

2 years ago

All isotopes of a particular element have the same atomic number. how then do the isotopes of a particular element differ?

White raven [17]

They have less or more neutrons. Isotopes have same number of protons but different number of neutrons.

4 0

3 years ago

Read 2 more answers

Which of the following elements matches the criteria below?

Tems11 [23]

Answer:

The answer to your question is below

Explanation:

1. Found in period 2. All the elements in the list are found in period 2.

a. F This option is correct

b. Be Beryllium is located in period two.

c. O also oxygen is found in period 2.

d. C Carbon is found in period 2.

2.- Can gain lose 4 electrons to become its nearest stable noble gas. Only Carbon.

a. F This option is wrong, F becomes stable when it gains 1 electron.

b. Be Beryllium becomes stable when it loses 2 electrons.

c. O Become stable when it gains 2 electrons.

d. C Become stable when it gains or loses 4 electrons.

4 0

2 years ago

The only bonds in a formula unit of CaF2 are __________. nonpolar covalent polar covalent ionic metallic

adell [148]

Answer:

ionic

Explanation:

Ionic bonds exist between Ca and F ions in CaF₂. Ionic bonds are interatomic bonds formed by the transfer of electrons from one atom to the other.

The donor atom here is Ca and it has two valence electrons. Fluorine is the receiving atom with 7 electrons in its outermost shell.

Ca would give one each of its two outermost electrons to the fluorine atoms to complete their octet. Ca ion would now resemble Argon and the flourine atoms would look more like Neon atoms.

This is an ionic bond

7 0

3 years ago