Answer:
(a) The anode electrode which comprises the zinc electrode being placed in a water solution with low oxygen concentration.
(b) Cathodic reaction is: 
⇒ 
Anodic reaction is: 
⇒
Explanation:
In the given problem, we have an oxygen-concentration cell consisting of two zinc electrodes. One is immersed in a water solution with a low oxygen concentration and the other in a water solution with a high oxygen concentration. The zinc electrodes are connected by an external copper wire.
(a) Which electrode will corrode?
The electrode that will corrode is the anode electrode which comprises the zinc electrode being placed in a water solution with low oxygen concentration.
(b) Write half-cell reactions for the anodic reaction and the cathodic reaction.
Cathodic reaction is: ⇒
Anodic reaction is: ⇒
<em>Answer:</em>
<em>Ether:</em>
Ether are organic compounds that contain ether functional group , in which oxygen atom is connected with two alkyl or aryl group.
They have general formula as follow
- R---O---R or R'---O----R or R'---O---R'
while R = Alkyl
R' = Aryl
Answer:
(E) changing temperature
Explanation:
Consider the following reversible balanced reaction:
aA+bB⇋cC+dD
If we know the molar concentrations of each of the reaction species, we can find the value of Kc using the relationship:
Kc = ([C]^c * [D]^d) / ([A]^a * [B]^b)
where:
[C] and [D] are the concentrations of the products in the equilibrium; [A] and [B] reagent concentrations in equilibrium; already; b; c and d are the stoichiometric coefficients of the balanced equation. Concentrations are commonly expressed in molarity, which has units of moles / 1
There are some important things to remember when calculating Kc:
- <em>Kc is a constant for a specific reaction at a specific temperature</em>. If you change the reaction temperature, then Kc also changes
- Pure solids and liquids, including solvents, are not considered for equilibrium expression.
- The reaction must be balanced with the written coefficients as the minimum possible integer value in order to obtain the correct value of Kc
Answer:
1.058337 grams of hydrogen and 2H2 + O2 ==> 2H2O hydrogen peroxide
mols H2 = grams/molar mass
Using the coefficients in the balanced equation, convert mols H2 to mols O2.
Now convert mols O2 to grams. That's grams mols O2 x molar mass O2.
and it could also produce H2O water but no air but it could make other things
