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NeX [460]
3 years ago
6

What is the speed of all forms of electromagnetic radiation in a vacuum

Physics
1 answer:
marysya [2.9K]3 years ago
3 0

Answer:

3.0 \cdot 10^8 m/s (speed of light)

Explanation:

Electromagnetic waves are oscillations of the electric and the magnetic field that occur in a plane perpendicular to the direction of travelling of the wave.

All electromagnetic waves travel in a vacuum at the same speed, whose value is:

c=3.0\cdot 10^8 m/s

And this value is called speed of light.

Electromagnetic waves are classified into 7 different types, depending on their wavelength/frequency. From highest to lowest frequency, we have:

Gamma rays

X-rays

Ultraviolet  radiation

Visible light

Infrared radiation

Microwaves

Radio waves

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Which two statements are true of electromagnetic waves?
Usimov [2.4K]

Answer:

B and C

Explanation:

Because EMWs are varying magnetic and electric radiation traveling at 90° to each other propagating energy form one place to another through vibration of these magnetic and electric fields

3 0
3 years ago
The gravitational force between two objects has a magnitude of F. If both masses were doubled and the distance between them doub
Fofino [41]

Answer:

F' = F

Explanation:

The gravitational force of attraction between two objects can be given by Newton's Gravitational Law as follows:

F = \frac{Gm_1m_2}{r^2}

where,

F = Force of attraction

G = Universal gravitational costant

m₁ = mass of first object

m₂ = mass of second object

r = distance between objects

Now, if the masses and the distance between them is doubled:

F' = \frac{G(2m_1)(2m_2)}{(2r)^2}\\\\F' = \frac{Gm_1m_2}{r^2}

<u>F' = F</u>

7 0
3 years ago
Describe two reasons why scientists are looking for alternatives to fossil fuels
Evgesh-ka [11]
1) It is because they produce a lot of pollution in the atmosphere
2) They are limited in number and can't be recycled

Hope this helps!
3 0
3 years ago
List and Explain three ways study groups benefit your learning
vodomira [7]

Answer:

The answer

Explanation:

Thinking together, Better friendship, Makes teacher happy.

4 0
3 years ago
Read 2 more answers
What is the change in potential energy if the distance separating the electron and proton is increased to 1.0 nm?
Vlada [557]

Answer:

Ep=-2.3*10^{-19}J

Explanation:

The change in potential energy can be expressed as:

Ep=K.\frac{q1.q2}{r}

where K is a constant with a value of 9*10^{9}\frac{N.m^{2}}{C^{2}}, q1 and q2 are the charges of the proton and the electron and r is the distance between them.

The charge for the proton is +1.6*10^{-19}C and the charge for the electron is -1.6*10^{-19}C.

Converting r=1.0nm to m:

1.0nm*\frac{1*10^{-9}m}{1.0nm}=1*10^{-9}m

Replacing values:

Ep=9*10^{9}\frac{N.m^{2}}{C^{2}}.\frac{(+1.6*10^{-19}C).(-1.6*10^{-19}C)}{1*10^{-9}m}

Ep=-2.3*10^{-19}J

5 0
3 years ago
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