Answer:
72J
Explanation:
distance moved is equal to 3m.then just substitute x with 3m.
Fx = (14(3) - 3.0(3)2)) N
Fx =(42-18)N
Fx =24N
W=Fx *S
W=24N*3m
W=72J
Answer:
313.6N
Explanation:
Given parameters;
Mass of the body = 50kg
Coefficient of friction = 0.64
Acceleration due to gravity = 9.81m/s²
Unknown:
Minimum force needed to move the body = ?
Solution:
To move this body, the minimum force must overcome the frictional force. So, the value of force that equals to that of the frictional force will set the body in motion.
Frictional force = Umg
U is the coefficient of friction
m is the mass
g is the acceleration due to gravity
Now insert the parameters and solve;
Frictional force = 0.64 x 50 x 9.8 = 313.6N
Answer:
Consider frames X and Y:
If X sees Y moving to his right then Y must see X moving to his right.
If this is not true then one can choose one frame over the other ( a favored frame and this is not allowed)
simple harmonic motion is a special type of periodic motion or oscillation where the restoring force is directly proportional to the displacement and acts in the direction opposite to that of displacement.
For simplicity, assume that the total mass of the compound is 100 g.
Therefore, by mass
Ca = 24.7 g, H = 1.2 g, C = 14.8 g, and O = 59.3 g
Converting these to moles
Mol = mass*1/atomic mass
Ca = 24.7*1/40.078 =0.6163 mol Ca
H = 1.2*1/1.01 = 1.1881 mol H
C = 14.8*1/12.01 = 1.2323 mol C
O = 59.3/16 = 3.7062 mol O
Next, divide all the mols by the smallest value obtained.
Ca: 0.6163/0.6163 = 1 mol Ca
H: 1.1881/0.6163 = 2 mol H
C: 1.2323/0.6163 = 2mol C
O: 3.7062/0.6163 = 6 mol O
Therefore, empirical formula of the compound is
CaH2C2O6
This compound is referred to as Calcium Bicarbonate