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Kay [80]
2 years ago
9

HELP! block is released from rest and slides down a frictionless ramp inclined at 30' from the horizontal. When the block reache

s the bottom the block-Earth system has mechanical energy Eo The
experiment is repeated, but now horizontal and vertical forces of magnitude F are exerted on the block while it slides, as shown above. When the block reaches the bottom, the mechanical energy
of the block-Earth system
A) is greater than Eo
B)is equal to Eo
C)is less than Eo
D)cannot be determined without knowing

Physics
1 answer:
Bumek [7]2 years ago
5 0

Answer:

A

Explanation:

the horizontal and vertical force acting on it consist a net force on the inclined direction (30degrees below the horizontal) you can tell by the length of the horizontal component (try to see the 30degree incline as horizontal, because that's the direction of the displacement). net work done on the system results in an increase in energy. i hope this can help :D, i'm also taking the ap physics 1 exam tommorow.

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Calculate a pendulum's frequency of oscillation (in Hz) if the pendulum completes one cycle in 0.5 s.
Marina86 [1]
Time taken to complete one oscillation for a pendulum is Time Period, T = 0.5 s 
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3 years ago
In a television set, electrons are accelerated from rest through a potential difference of 20 kV. The electrons then pass throug
Svetradugi [14.3K]

Answer: Fmax = 5.54*10^-12 N

Explanation: From the question, we have the potential difference (V) =20kv = 20,000v and strength of magnetic field (B) =0.41 T.

The maximum force experienced by a charge of magnitude (q) is given as

Fmax = qvB

Where v = velocity of electron.

The velocity of the electron can be gotten by using the work energy theorem.

The kinetic energy of the electron (mv²/2) equals the work done needed to accelerate it.

mv²/2 = qV.

Where m = mass of an electronic charge = 9.11×10^-31 kg, q = magnitude of an electronic charge = 1.609×10^-19 c, v = velocity of electron, V = potential difference = 20,000v.

By substituting the parameters, we have that

(9.11×10^-31 × v²)/2 = 1.609×10^-19 × 20000

(9.11×10^-31 × v²) = 1.609×10^-19 × 20000 ×2

v² = (1.609×10^-19 × 20000 ×2)/9.11×10^-31

v² = 64.36*10^(-16)/9.11×10^-31

v² = 7.0647×10^15

v = √7.0647×10^15

v = 8.40×10^7 m/s

Fmax = 1.609×10^-19 × 8.40×10^7 × 0.41

Fmax = 5.54*10^-12 N

7 0
3 years ago
When a solute can't be dissolved in a solvent what is it called called?​
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Answer: SATURATED

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When a solute can no longer be dissolved it is considered "saturated" as is.

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2 years ago
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Answer:

Explanation:

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