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Kay [80]
3 years ago
9

HELP! block is released from rest and slides down a frictionless ramp inclined at 30' from the horizontal. When the block reache

s the bottom the block-Earth system has mechanical energy Eo The
experiment is repeated, but now horizontal and vertical forces of magnitude F are exerted on the block while it slides, as shown above. When the block reaches the bottom, the mechanical energy
of the block-Earth system
A) is greater than Eo
B)is equal to Eo
C)is less than Eo
D)cannot be determined without knowing

Physics
1 answer:
Bumek [7]3 years ago
5 0

Answer:

A

Explanation:

the horizontal and vertical force acting on it consist a net force on the inclined direction (30degrees below the horizontal) you can tell by the length of the horizontal component (try to see the 30degree incline as horizontal, because that's the direction of the displacement). net work done on the system results in an increase in energy. i hope this can help :D, i'm also taking the ap physics 1 exam tommorow.

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If a proton were released in the electric field above, what direction would it move?
Afina-wow [57]

Answer:

d because the proton would move towards the negative plate

Explanation:

5 0
3 years ago
You are riding in the passenger seat of a car as it goes around a tight turn. You slide across the seat to the passenger side do
DochEvi [55]

Answer:

1. b. The door is exerting a centripetal force on you that balances the centrifugal force of the turn.

2. b. There is no net force acting on the object.

Explanation:

1. This is because as you move to the right due to the centrifugal force of the turn, a corresponding centripetal force acts on you due to the door which does not allow you fall out of the car since,<u> the door is exerting a centripetal force on you that balances the centrifugal force of the turn. </u>

So, the answer is b

2. This is because, since the object moves at a constant speed and thus does not accelerate, no net force can act on it since, a net force would imply that the object accelerates. Note that a constant speed does not imply that no force acts on it. It only shows that the resultant or net force is zero since the object does not accelerate.

So, <u>there is no net force acting on the object. </u>

So, b is the answer.

6 0
2 years ago
A student walks (2.9±0.1)m, stops and then walks another (3.9 ±0.2)m in the same directionWith the given uncertainties, what is
Anika [276]

Answer:

The smallest distance the student that the student could be possibly be from the starting point is 6.5 meters.

Explanation:

For 2 quantities A and B represented as

A\pm \Delta A and B\pm \Delta B

The sum is represented as

Sum=(A+B)\pm (\Delta A+\Delta B)

For the the values given to us the sum is calculated as

Sum=(2.9+3.9)\pm (0.1+0.2)

Sum=6.8\pm 0.3

Now the since the uncertainity inthe sum is \pm 0.3

The closest possible distance at which the student can be is obtained by taking the negative sign in the uncertainity

Thus closest distance equals 6.8-0.3=6.5meters

3 0
3 years ago
Two small insulating spheres with radius 3.50×10−2 m are separated by a large center-to-center distance of 0.555 m. One sphere i
xz_007 [3.2K]

Answer:

E = 7.83 \times 10^5 N/C

Explanation:

Since we know that two sphere is oppositely charged so net electric field at the mid point of two balls will be sum of the electric field due to each ball at the mid point

So we know that

E = \frac{kq_1}{r^2} + \frac{kq_2}{r^2}

here we know that

q_1 = 4.20 \mu C

q_2 = 2.50 \mu C

r = \frac{0.555}{2}

so we have

E = \frac{(9\times 10^9)(4.20 + 2.50) \times 10^{-6}}{0.2775^2}

E = 7.83 \times 10^5 N/C

4 0
3 years ago
Why is. A paper clip attracted to a magnet, while a pencil is not?
Akimi4 [234]
The paper clip did because it is a conductor. A pencil is made with wood and that is an insulator.
7 0
3 years ago
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