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3 years ago

8

The EPA scientist measures the pH level in one area of a river to be lower than normal and writes that a pollutant must have bee

n discharged from a factory just upstream. This is an example of

2 answers:

shutvik [7]3 years ago

4 0

Its an example of inference.

HACTEHA [7]3 years ago

3 0

Answer:

INFERENCE.

next question answer:

A LINE GRAPH.

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2.4 g of a solid is added to 91 g of water. What is the mass % concentration of the solution?

vladimir2022 [97]

Answer:

2.64%

Explanation:

mass percent = (grams of solute / grams of solution) x 100

mass percent = (2.4 / 91) × 100

mass percent = 2.64% to 3sf

8 0

1 year ago

What two properties of a gas depend on its container

katrin [286]

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3 years ago

How can you tell baking a cake produces a chemical change?

11111nata11111 [884]

Answer: see below

Explanation:

1. Change in smell

2. Heat given off

3. New substance (cake) cannot be separated into the original ingredients

For detailed, step-by-step explanations you can visit my fiverr account: kesja_

I provide detailed explanations for math questions for as little as $1!

7 0

2 years ago

Bromine reacts with nitric oxide to form nitrosyl bromide as shown in this reaction: br2(g) + 2 no(g) → 2 nobr(g) a possible mec

Svetach [21]

The overall reaction is given by:

$Br_{2}(g) + 2 NO(g) \rightarrow 2 NOBr(g)$

The fast step reaction is given as:

$NO(g) + Br_{2}(g) \rightleftharpoons NOBr_{2}(g) (fast; k_{eq}= \frac{k_{1}}{k_{-1}})$

The slow step reaction is given as:

$NOBr_{2}(g) + NO(g) \rightarrow 2 NOBr(g)$ (slow step $k_{2}$ )

Now, the expression for the rate of reaction of fast reaction is:

$r_{1}=k_{1}[NO][Br_{2}]-k_{-1}[NOBr_{2}]$

The expression for the rate of reaction of slow reaction is:

$r_{2}=k_{2}[NOBr_{2}] [NO]$

Slow step is the rate determining step. Thus, the overall rate of formation is the rate of formation of slow reaction as $[NOBr_{2}]$ takes place in this reaction.

The expression of rate of formation is:

$\frac{d(NOBr)}{dt}=r_{2}$

= $k_{2}[NOBr_{2}][NO]$ (1)

Now, consider that the fast step is always is in equilibrium. Therefore, $r_{1}=0$

$k_{1}[NO][Br_{2}]= k_{-1}[NOBr_{2}]$

$[NOBr_{2}] = \frac{k_{1}}{k_{-1}}[NO][Br_{2}]$

Substitute the value of $[NOBr_{2}]$ in equation (1), we get:

$\frac{d(NOBr)}{dt}=k_{2}[NOBr_{2}][NO]$

= $k_{2} \frac{k_{1}}{k_{-1}}[NO][Br_{2}][NO]$

= $\frac{k_{1}k_{2}}{k_{-1}}[NO]^{2}[Br_{2}]$

Thus, rate law of formation of $NOBr$ in terms of reactants is given by $\frac{k_{1}k_{2}}{k_{-1}}[NO]^{2}[Br_{2}]$ .

4 0

3 years ago

A flask has a mass of 78.23g when empty and 593.63g when filled with water.When the same flask is filled with concentrateds ulfu

butalik [34]

Answer:

Density of concentrated H2SO4 = 1.99g/cm^3 = 1991.79Kg/m^3

Explanation:

mass of empty flask = 78.23g mass of flask filled when with water = 593.63g.

mass of flask filled when with concentrateds sulfuric acid, H2SO4 = 1026.57g

Mass of water = (mass of flask filled when with water) -

(mass of empty flask) = 593.63g - 78.23g = 515.4g

Volume of flask = volume of water = volume of concentrateds sulfuric acid, H2SO4 =

(mass of water)/ density of water) = 515.4g/1.00g/cm^3 = 515.4cm^3

The density of concentrated sulfuric acid is given by

Density of concentrated H2SO4 = (mass of H2SO4) ÷ (volume of H2SO4) = 1026.57g/515.4cm^3 = 1.99g/cm^3 = 1991.79Kg/m^3

7 0

2 years ago