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NikAS [45]
3 years ago
9

A 60-vibration-per-second wave travels 30 meters in 1 second. Its frequency isA) 30 hertz and it travels at 60 m/s.B) 60 hertz a

nd it travels at 30 m/s.C) 1800 hertz and it travels at 2 m/s.
Physics
1 answer:
fredd [130]3 years ago
3 0

Answer:

B) 60 hertz and it travels at 30 m/s

Explanation:

The frequency of a wave corresponds to the number of complete vibrations per second. The wave in this problem has 60 vibrations per second, so its frequency is

f=\frac{60 vibrations}{ 1 s}=60 Hz

The speed of the wave instead is given by the distance travelled divided by the time taken. In this problem:

d = distance travelled = 30 m

t = time taken = 1 s

So, the speed of the wave is

v=\frac{d}{t}=\frac{30 m}{1 s}=30 m/s

so, the correct answer is

B) 60 hertz and it travels at 30 m/s

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Sorry Man If you ask this question no one wants to write an essay and waste their time. You are smart enough to write an essay.
7 0
3 years ago
A tank has the shape of an inverted circular cone with height 16m and base radius 3m. The tank is filled with water to a height
rewona [7]

Answer:

W=17085KJ

Explanation:

From the question we are told that:

Height H=16m

Radius R=3

Height of water H_w=9m

Gravity g=9.8m/s

Density of water \rho=1000kg/m^3

Generally the equation for Volume of water is mathematically given by

 dv=\pi*r^2dy

 dv=\frac{\piR^2}{H^2}(H-y)^2dy

Where

   y is a random height taken to define dv

Generally the equation for Work done to pump water is mathematically given by

 dw=(pdv)g (H-y)

Substituting dv

 dw=(p(=\frac{\piR^2}{H^2}(H-y)^2dy))g (H-y)

 dw=\frac{\rho*g*R^2}{H^2}(H-y)^3dy

Therefore

 W=\int dw

 W=\int(\frac{\rho*g*R^2}{H^2}(H-y)^3)dy

 W=\rho*g*R^2}{H^2}\int((H-y)^3)dy)

 W=\frac{1000*9.8*3.142*3^2}{9^2}[((9-y)^3)}^9_0

 W=3420.84*0.25[2401-65536]

 W=17084965.5J

 W=17085KJ

 

'

'

4 0
3 years ago
Two blocks joined by a string have masses of 6 and 9 kg. They rest on a frictionless horizontal surface. A 2nd string, attached
Tom [10]

Answer:

12N

Explanation:

Suppose the string mass is negligible, the total mass of the 2 block system is 6 + 9 = 15 kg

So the acceleration of the system when subjected to 30N force is

a = F / M = 30 / 15 = 2 m/s2

So both blocks would have the same acceleration, however, the force acting on the 6kg block would have a magnitude of

f = am = 2 * 6 = 12N

This is the tension in the string between the blocks

5 0
3 years ago
A tray is moved horizontally back and forth in simple harmonic motion at a frequency of f = 2.07 Hz. On this tray is an empty cu
Anettt [7]

Answer:

Explanation:

Given

Frequency of SHM is f=2.07\ Hz

Amplitude of SHM is A=3.13\ cm

Cup begins to slip when it overcomes the friction force

Friction force F_s=\mu mg

Applied force F=ma

ma=\mu mg

a=\mu g

and maximum acceleration during SHM is

a=A\omega ^2

a=A(2\pi f)^2

a=3.13\times 10^{-2}\times (2\pi 2.07)^2

a=5.296\ m/s^2

\mu =\frac{a}{g}

\mu =\frac{5.296}{9.8}=0.54

6 0
4 years ago
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Which of the following is not an example of centripetal acceleration?
Amanda [17]
An apple falling to the ground is not an example of centripetal acceleration.
5 0
3 years ago
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