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3 years ago

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A 60-vibration-per-second wave travels 30 meters in 1 second. Its frequency isA) 30 hertz and it travels at 60 m/s.B) 60 hertz a

nd it travels at 30 m/s.C) 1800 hertz and it travels at 2 m/s.

1 answer:

fredd [130]3 years ago

3 0

Answer:

B) 60 hertz and it travels at 30 m/s

Explanation:

The frequency of a wave corresponds to the number of complete vibrations per second. The wave in this problem has 60 vibrations per second, so its frequency is

$f=\frac{60 vibrations}{ 1 s}=60 Hz$

The speed of the wave instead is given by the distance travelled divided by the time taken. In this problem:

d = distance travelled = 30 m

t = time taken = 1 s

So, the speed of the wave is

$v=\frac{d}{t}=\frac{30 m}{1 s}=30 m/s$

so, the correct answer is

B) 60 hertz and it travels at 30 m/s

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pogonyaev

Hello,

The answer is option A "Venus".

Reason:

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3 years ago

Read 2 more answers

One end of an insulated metal rod is maintained at 100 ∘C and the other end is maintained at 0.00 ∘C by an ice–water mixture. Th

lozanna [386]

Answer:

$k=105.0359\times 10^4\,W.m^{-1}.K^{-1}$

Explanation:

Given:

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temperature at the cooler end, $T_C=0^{\circ}C$

length of rod through which the heat travels, $dx=0.7\,m$

cross-sectional area of rod, $A=1.1\times 10^{-4}\,cm^2$

mass of ice melted at zero degree Celsius, $m=8.7\times 10^{-3}\,kg$

time taken for the melting of ice, $t=15\times60=900\,s$

thermal conductivity k=?

By Fourier's Law of conduction we have:

$\dot{Q}=k.A.\frac{dT}{dx}$ ......................................(1)

where:

$\dot{Q}$ =rate of heat transfer

dT= temperature difference across the length dx

Now, we need the total heat transfer according to the condition:

we know the latent heat of fusion of ice, $L = 334000\,J.kg^{-1}$

$Q=m.L$

$Q=8.7\times 10^{-3}\times 334000$

$Q=2905.8\,J$

Now the heat rate:

$\dot{Q}=\frac{Q}{t}$

$\dot{Q}=\frac{2905.8}{900}$

$\dot{Q}=3.2287\,W$

Now using eq,(1)

$3.2287=k\times 1.1\times 10^{-4} \times \frac{100}{0.7}$

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3 years ago

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tia_tia [17]

Answer:

Explanation:

A mass of 700 kg will exert a force of

700 x 9.8

= 6860 N.

Amount of compression x = 4 cm

= 4 x 10⁻² m

Force constant K = force of compression / compression

= 6860 / 4 x 10⁻²

= 1715 x 10² Nm⁻¹.

Let us take compression of r at any moment

Restoring force by spring

= k r

Force required to compress = kr

Let it is compressed by small length dr during which force will remain constant.

Work done

dW = Force x displacement

= -kr -dr

= kr dr

Work done to compress by length d

for it r ranges from 0 to -d

Integrating on both sides

W = $\int\limits^{-4}_0 {kr} \, dr$

= [ kr²/2]₀^-4

= 1/2 kX16X10⁻⁴

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Yuliya22 [10]

Answer:

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Explanation:

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2 years ago

in a softball game, a batter hits the ball at the velocity of 27m/s and angle of 40 shown below. What is the maximum range of th

Nata [24]

Answer:

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Explanation:

We have,

Initial speed of the ball is 27 m/s

It is projected at an angle of 40 degrees

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Plugging all the values we get :

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