Answer:
(a) FN = m (g - 
)
(b) vmin = 17.146 m/s
Explanation:
The radius of the arc is
r = 30m
The normal force acting on the car form the highest point is
FN = m (g - )
If the normal force become 0 we have
m (g - ) = 0
or
g - = 0
This way, when FN = 0, then v = vmin, so
g - 
= 0
vmin = ![\sqrt[.]{g*r}](https://tex.z-dn.net/?f=%5Csqrt%5B.%5D%7Bg%2Ar%7D)
= ![\sqrt[.]{9.8 m/s^{2} * 30m } = 17.146 m/s](https://tex.z-dn.net/?f=%5Csqrt%5B.%5D%7B9.8%20m%2Fs%5E%7B2%7D%20%2A%2030m%20%7D%20%3D%2017.146%20m%2Fs)
Answer:
The resistivity of materials depends on the temperature as ρt = ρ0 [1 + α (T – T0). This is the equation that shows the relationship between the resistivity and the temperature.
hope it helps
During a car crash, energy is transferred from the vehicle to whatever it hits, be it another vehicle or a stationary object. ... The object that was struck will either absorb the energy thrust upon it or possibly transfer that energy back to the vehicle that struck it.
I HOPE THIS HELPSS???
Mark me brainliest
Answer: E) A) salt water.
Explanation:
E) In equilibrium, pressure exerts equally in all directions, so for a given depth, the pressure is the same for all points located at the same depth, and it can be written as follows:
p = p₀ + ρ.g.h, where p₀ = atmospheric pressure, ρ=fluid density, h=depth from the surface.
A) The buoyant force, as discovered by Archimedes, is an upward force, that opposes to the weight of an object (as it is always downward), and is equal to the weight of the volume of the liquid that the object removes, which means that is proportional to the density of the liquid.
As salt water is denser than fresh water, the buoyant force exerted by the salt water is always greater than the one produced by the fresh water, so objects will float more easily in salt water than in fresh water.
In the limit, it is possible that one object float in salt water and sink in fresh water.
At rest because if the distance is not changing, then it is not moving any further, so it must not be moving! The time keeps going no matter what, so the distance, whether it is 0 m or 10,000 km, if the y is horizontal the distance does not change.
