What is the age of The Universe and how big is it? ⭐

Electromagnetic waves are commonly referred to as _________

mart [117]

It’s going to be both answer A and B but if you can only answer one then it’s going to be B

3 0

2 years ago

A girl and a boy are riding on a merry go round that is turning at a constant rate. The girl is near the outer edge, and the boy

galina1969 [7]

Answer:

The girl has greater tangential acceleration

Explanation:

The angular acceleration ( $\alpha$ ) of the merry go round is equal to the rate of the change of the angular velocity, $\omega$ :

$\alpha = \frac{d\omega}{dt}$

Since all the points of the merry go round complete 1 circle in the same time, the angular velocity of each point of the merry go round is the same, and so all the points also have the same angular acceleration.

The tangential acceleration instead is given by

$a_t = \alpha r$

where

$\alpha$ is the angular acceleration

r is the distance from the centre of the merry go round

Since the girl is near the outer edge and the boy is closer to the centre, the value of r for the girl is larger than for the boy, so the girl has greater tangential acceleration.

5 0

3 years ago

If the Sun were to stop shining, Earth would stop receiving heat and light within about eight minutes. Earth, however, would rem

hjlf

If The Sun Went Out, How Long Could Life On Earth Survive? ... (which is actually physically impossible), the Earth would stay warm—at least ... from the planet's core would equal theheat that the Earth radiates into space, ... Photosynthesis would halt immediately, and most plantswould die in a few weeks.

6 0

3 years ago

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Suppose that you can throw a projectile at a large enough v0 so that it can hit a target a distance R downrange. Given that you

NikAS [45]

Answer:

Theta1 = 12° and theta2 = 168°

The solution procedure can be found in the attachment below.

Explanation:

The Range is the horizontal distance traveled by a projectile. This diatance is given mathematically by Vo cos(theta) t. Where t is the total time of flight of the projectile in air. It is the time taken for the projectile to go from starting point to finish point. This solution assumes the projectile finishes uts motion on the same horizontal level as the starting point and as a result the vertical displacement is zero (no change in height).

In the solution as can be found below, the expression to calculate the range for any launch angle theta was first derived and then the required angles calculated from the equation by substituting the values of the the given quantities.