It is customary to work in SI units.
Calculate the volume of the concrete.
V = 3.7*2.1*5.8 cm³ = 45.066 cm³ = 45.066 x 10 ⁻⁶ m³
The mass is 43.8 g = 43.8 x 10⁻³ kg
The density is mass/volume.
Density = (43.8 x 10⁻³ kg)/(45.066 x 10⁻⁶ m³) = 971.9 kg/m³
Answer: 971.9 kg/m³
Yes there is an elastic collision in physics its when a collision occurs but no kinetic energy is loss. We study them in order to understand how to conserve momentum.
The vertical component is = vsinx m/s
If you know the angle, substitute the value of x.
If you know the velocity at which it is moving, substitute it for v
Hope it helps :)
Work = force x distance
You can see time doesn’t matter (if we were talking about power, which is the RATE at which work is performed, that would be a different story).
W = 2 x 5 = 10 foot-pounds of work
Foot-pounds are gross units. Better to work in SI units when you can!
Answer:
28.81 m
Explanation:
Ff = -123
m * a = -123
(29.8+10.3) * a = -123
a = -123/40.1 = -3.07
We know,
v^2 = u^2 + 2as
0^2 = 13.3^2 + 2*(-3.07)*s
s = 176.89/6.14 = 28.81
[ If there's a problem with the solution, pleaase let me know ]
