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Drupady [299]
3 years ago
8

Process in which a nucleus undergoes spontaneous transformation into

Chemistry
1 answer:
Sedbober [7]3 years ago
8 0

Answer: Radioactive decay

Explanation:

Radioactive decay involves the emission of radiation by the nucleus of an element through the process of disentegration of the nucleus.

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A gas has a volume of 590 mL at temperature of -55.0 C. What volume will the gas occupy at 30.0 C show your work
DENIUS [597]
Data:
V_{initial} = 590\:mL
T_{initial} = -55.0^0C
converting to Kelvin
TK = TC + 273
TK = -55.0 + 273 → TK = 218.0 → T_{initial} = 218.0\:K
V_{final} = ? (in\:milliliters)
T_{final} = 30.0^0C
TK = TC + 273
TK = 30.0 + 273 → TK = 303.0 → T_{final} = 303.0\:K

By the first Law of Charles and Gay-Lussac, we have: 
\frac{ V_{i} }{ T_{i} } = \frac{ V_{f} }{ T_{f} }

Solving:
\frac{ V_{i} }{ T_{i} } = \frac{ V_{f} }{ T_{f} }
\frac{ 590 }{ 218.0 } = \frac{ V_{f} }{ 303.0 }
Product of extremes equals product of means:
218.0* V_{f} = 590*303.0
218.0 V_{f} = 178770
V_{f} = \frac{178770}{218.0}
\boxed{\boxed{V_{f} \approx 820.04\:mL}}\end{array}}\qquad\quad\checkmark
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Explanation:

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All the following are equal to Avogadro's number EXCEPT a. the number of atoms of bromine in 1 mol Br₂.

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However, each molecule contains two atoms of Br, so there are

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