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DaniilM [7]
3 years ago
12

How to fronts and air masses affect weather?

Chemistry
1 answer:
zavuch27 [327]3 years ago
5 0

Answer:

Warm fronts often bring stormy weather as the warm air mass at the surface rises above the cool air mass, making clouds and storms. Warm fronts move more slowly than cold fronts because it is more difficult for the warm air to push the cold, dense air across the Earth's surface.

Explanation:

Good luck!

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How many joules are needed to warm 675 grams of water (specific heat= 4.186 J/g degrees Celsius) from 12 degrees Celsius to 85 d
Naya [18.7K]
85-12 = 73 degrees needed
4.186 J/degree Celsius, so 
73 degrees * 4.186 J/degree = 305.578 J to raise 1 gram 73 degrees
there are 675 grams, so 305.578 * 675 = 206265.15 J

2.06 x 10^5 J are needed
3 0
3 years ago
Read 2 more answers
Data was collected by students in an acid base titration lab. They used 1.63 M Ca(OH)2(AQ)
jenyasd209 [6]

Answer:

3.8 M

Explanation:

Volume of acid used VA= 57.0 - 37.5 = 19.5 ml

Volume of base used VB= 67.8 - 45.0 = 22.8 ml

Equation of the reaction

2HNO3(aq) + Ca(OH)2(aq) --------> Ca(NO3)2(aq) + 2H2O(l)

Number of moles of acid NA= 2

Number of moles of base NB= 1

Concentration of acid CA= ???

Concentration of base CB= 1.63 M

CAVA/CBVB = NA/NB

CAVANB = CBVBNA

CA= CBVBNA/VANB

CA= 1.63 × 22.8 × 2/ 19.5 × 1

CA= 3.8 M

HENCE THE MOLARITY OF THE ACID IS 3.8 M.

6 0
3 years ago
To evaluate R in an Ideal gas Law (PV=nRT), the Volume of a gas is measured in ____ , while the temperature of a gas is measured
Vika [28.1K]
L (litter)
K (kelvin)
3 0
2 years ago
Bacteria that live around deep-sea, hot-water vents obtain energy by oxidizing inorganic hydrogen sulfide belched out by the ven
Ber [7]

Answer:

Chemoautotrophs

Explanation:

Autotrophs are groups of organisms that are capable of manufacturing their own food (organic molecules) through the fixation of carbon dioxide. There are two types of autotrophs:

  • <em>Photoautotrophs fix carbon dioxide by using light as the energy for driving the process.</em>
  • <em> </em><em>Chemoautotrophs f</em><em>ix carbon dioxide by  using energy from the oxidation of inorganic molecules such as magnesium, or sulfur.</em>

Chemoautotrophs usually inhabit extreme environment such hot vents, deep sea, etc.

3 0
3 years ago
An acetate buffer solution is prepared by combining 50. mL of a 0.20 M acetic acid, HC2H3O2 (aq), and 50. mL of 0.20 M sodium ac
Gala2k [10]

Answer:

B. CH3COOH pH > 4.7 (4.8)

Explanation:

  • CH3COOH + NaOH ↔ CH3COONa + H2O
  • CH3COONa + NaOH ↔ CH3COONa

∴ mol NaOH = (5 E-3 L)*(0.10 mol/L) = 5 E-4 mol

⇒ mol CH3COOH = (0.05 L)*(0.20 mol/L) = 0.01 mol

⇒ <em>C</em> CH3COOH = (0.01 mol - 5 E-4 mol) / (0.105 L)

⇒ <em>C</em> CH3COOH = 0.0905 M

∴ mol CH3COONa = (0.05 L )*(0.20 mol/L) = 0.01 mol

⇒ <em>C</em> CH3COONa =  (0.01 mol + 5 E-4 mol) / (0.105 L )

⇒ <em>C</em> CH3COONa = 0.1 M

∴ Ka = ([H3O+]*(0.1 + [H3O+])) / (0.0905 - [H3O+]) = 1.75 E-5

⇒ 0.1[H3O+] + [H3O+]² = (1.75 E-5)*(0.0905 - [H3O+])

⇒ [H3O+]² 0.1[H3O+] = 1.584 E-6 - 1.75 E-5[H3O+]

⇒ [H3O+]² + 0.1000175[H3O+] - 1.584 E-6 = 0

⇒ [H3O+] = 1.5835 E-5 M

∴ pH = - Log [H3O+]

⇒ pH = - Log (1.5835 E-5)

⇒ pH = 4.8004 > 4.7

7 0
3 years ago
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