Hi I am Mary and I need help solving these questions
1 answer:
You might be interested in
Answer: 67.23 L
Explanation:
According to avogadro's law, 1 mole of every substance occupies 22.4 L at STP and contains avogadro's number of particles.
To calculate the number of moles, we use the equation:
Putting in the values we get:
1 mole of methane occupies = 22.4 L
Thus 3 moles of methane occupy =
Thus volume of 48 grams of methane gas is 67.23 L