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Stolb23 [73]
3 years ago
9

Calculate the freezing point of a 12.25 m 12.25m aqueous solution of propanol. Freezing point constants can be found in the list

of colligative constants.
Chemistry
1 answer:
vichka [17]3 years ago
5 0

Answer:

∆t(f) = 49.755C

Explanation:

Freezing point is defined as the point in which a liquid changes from liquid to solid state. Therefore, to calculate the freezing point of aqueous solution of propanol

∆t = k × I × m

Where k is cryscopic constant =

I = vant Hoff factor = 2

M = molar concentration = 12.25m

∆t (f) = 1.9 × 12.25 × 2 = 49.755C

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